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How to Override compareTo Method in Java? – GeeksforGeeks

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Summary of article content: Articles about comparable – How to override compareTo (Java) – Stack Overflow public User implements Comparable ; @Overre public int compareTo(User user) { return user.age >= age ? -1 : 0; } ; public · sort · new … …
Most searched keywords: Whether you are looking for comparable – How to override compareTo (Java) – Stack Overflow public User implements Comparable ; @Overre public int compareTo(User user) { return user.age >= age ? -1 : 0; } ; public · sort · new …
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comparable – How to override compareTo (Java) – Stack Overflow

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Summary of article content: Articles about Cómo anular compareTo (Java) – PeakU with field int age , constructor and overred method of interface Comparable: @Overre public int compareTo(User user) { return user.age > … …
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Soy principiante en programación y tengo dos clases. Primera clase es:
```
 public class User implements Comparable<User>
```
con campo int age , constructor y método anulado de interfaz Comparable:
```
 @Override public int compareTo(User user) { return user.age >= age ? -1 : 0; }
```
La segunda clase es public class SortUser con un método para hacer una colección Set a partir de una Lista:
```
 public Set<User> sort(List<User> list) { Set<User> result = new TreeSet<>(); for (User user : list) { result.add(user); } return result; }
```
Me parece que todos los objetos de User en un conjunto deben ordenarse, pero cuando hice una lista con 3 objetos de User …
```
 User a = new User(1); User b = new User(2); User c = new User(3); List<User> list = new ArrayList<>(); list.add(c); list.add(a); list.add(b);
```
(Ahora el orden de la lista es: 312 ) …y creó un Set ( TreeSet ) de esa lista:
```
 SortUser sortUser = new SortUser(); Set<User> set = sortUser.sort(list);
```
Al final tengo un set con ese orden: 13 , significa que solo hay dos objetos en el set . ¿Qué está yendo mal?
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Cómo anular compareTo (Java) – PeakU

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Summary of article content: Articles about Cómo anular compareTo (Java) – PeakU 2. Overre compare Method … It works the same way as compareTo in Comparable Interface. Now, you can explicitly define how to compare between two File objects … …
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Soy principiante en programación y tengo dos clases. Primera clase es:
```
 public class User implements Comparable<User>
```
con campo int age , constructor y método anulado de interfaz Comparable:
```
 @Override public int compareTo(User user) { return user.age >= age ? -1 : 0; }
```
La segunda clase es public class SortUser con un método para hacer una colección Set a partir de una Lista:
```
 public Set<User> sort(List<User> list) { Set<User> result = new TreeSet<>(); for (User user : list) { result.add(user); } return result; }
```
Me parece que todos los objetos de User en un conjunto deben ordenarse, pero cuando hice una lista con 3 objetos de User …
```
 User a = new User(1); User b = new User(2); User c = new User(3); List<User> list = new ArrayList<>(); list.add(c); list.add(a); list.add(b);
```
(Ahora el orden de la lista es: 312 ) …y creó un Set ( TreeSet ) de esa lista:
```
 SortUser sortUser = new SortUser(); Set<User> set = sortUser.sort(list);
```
Al final tengo un set con ese orden: 13 , significa que solo hay dos objetos en el set . ¿Qué está yendo mal?
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Cómo anular compareTo (Java) – PeakU

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Error 403 (Forbidden)

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How to Override compareTo Method in Java?

As we know, there are basically two types of sorting technique in Java:

First is internal sorting i.e that uses predefined sorting method ascending order Arrays.sort() for Primitive class arrays and wrapper class arrays and Collections.sort() for collections both methods sort the elements in ascending order.

for Primitive class arrays and wrapper class arrays and for both methods sort the elements in ascending order. The second technique is for sorting the elements is using the comparator or comparable interface in a class. Comparator Interface: Implement the comparator interface in the class and override compare() method or pass the new comparator as the second argument in the sorting methods and change the sorting order according to the requirements. Comparator only works for wrapper type arrays and for collections like vector, ArrayList, etc.

Comparable Interface: This interface implements a single sorting technique, and it affects the whole class. The comparable interface provides a compareTo() method to sort the elements.

To summarize, in Java, if sorting of objects needs to be based on natural order then use the compareTo() method of Comparable Interface. For Integers default natural sorting order is ascending and for Strings it is alphabetical. Whereas, if you’re sorting needs to be done on attributes of different objects, or customized sorting then use compare() of Comparator Interface.

Overriding of the compareTo() Method

In order to change the sorting of the objects according to the need of operation first, we have to implement a Comparable interface in the class and override the compareTo() method. Since we have to sort the array of objects, traditional array.sort() method will not work, as it used to work on primitive types, so when we call the Arrays.sort() method and pass the object array, it will search, whether we have overridden the compareTo() method or not. Since we have overridden the compareTo() method, so objects will be compared by using this compareTo() methods, based on the age.

Java

import java.util.*; public class GFG implements Comparable { String name; int age; GFG(String name, int age) { this .name = name; this .age = age; } public int getage() { return age; } public String getname() { return name; } public static void main(String[] args) { GFG ob[] = new GFG[ 4 ]; ob[ 0 ] = new GFG( “Aayush” , 14 ); ob[ 1 ] = new GFG( “Ravi” , 12 ); ob[ 2 ] = new GFG( “Sachin” , 19 ); ob[ 3 ] = new GFG( “Mohit” , 20 ); Arrays.sort(ob); for (GFG o : ob) { System.out.println(o.name + ” ” + o.age); } ArrayList objects = new ArrayList<>(); GFG newObject1 = new GFG( “Rohan Devaki” , 20 ); objects.add(newObject1); GFG newObject2 = new GFG( “Algorithammer” , 22 ); objects.add(newObject2); Collections.sort(objects); for (GFG o : objects) { System.out.format( “%s %d

” , o.name, o.age); } } @Override public int compareTo(GFG o) { if ( this .age > o.age) { return 1 ; } else if ( this .age < o.age) { return - 1 ; } else { return 0 ; } } } Output Ravi 12 Aayush 14 Sachin 19 Mohit 20 Rohan Devaki 20 Algorithammer 22

How to override compareTo (Java)

I’m a beginner in programming and I have two classes. First class is:

public class User implements Comparable

with field int age , constructor and overrided method of interface Comparable:

@Override public int compareTo(User user) { return user.age >= age ? -1 : 0; }

Second class is public class SortUser with a method to make a Set collection from a List:

public Set sort(List list) { Set result = new TreeSet<>(); for (User user : list) { result.add(user); } return result; }

It seems to me that all User objects in a Set should be sorted, but when I made a List with 3 User objects…

User a = new User(1); User b = new User(2); User c = new User(3); List list = new ArrayList<>(); list.add(c); list.add(a); list.add(b);

(Now the list’s order is: 312 ) …and created a Set ( TreeSet ) from that list:

SortUser sortUser = new SortUser(); Set set = sortUser.sort(list);

How to Override compareTo Method in Java?

As we know, there are basically two types of sorting technique in Java:

First is internal sorting i.e that uses predefined sorting method ascending order Arrays.sort() for Primitive class arrays and wrapper class arrays and Collections.sort() for collections both methods sort the elements in ascending order.

for Primitive class arrays and wrapper class arrays and for both methods sort the elements in ascending order. The second technique is for sorting the elements is using the comparator or comparable interface in a class. Comparator Interface: Implement the comparator interface in the class and override compare() method or pass the new comparator as the second argument in the sorting methods and change the sorting order according to the requirements. Comparator only works for wrapper type arrays and for collections like vector, ArrayList, etc.

Comparable Interface: This interface implements a single sorting technique, and it affects the whole class. The comparable interface provides a compareTo() method to sort the elements.

To summarize, in Java, if sorting of objects needs to be based on natural order then use the compareTo() method of Comparable Interface. For Integers default natural sorting order is ascending and for Strings it is alphabetical. Whereas, if you’re sorting needs to be done on attributes of different objects, or customized sorting then use compare() of Comparator Interface.

Overriding of the compareTo() Method

In order to change the sorting of the objects according to the need of operation first, we have to implement a Comparable interface in the class and override the compareTo() method. Since we have to sort the array of objects, traditional array.sort() method will not work, as it used to work on primitive types, so when we call the Arrays.sort() method and pass the object array, it will search, whether we have overridden the compareTo() method or not. Since we have overridden the compareTo() method, so objects will be compared by using this compareTo() methods, based on the age.

Java

import java.util.*; public class GFG implements Comparable { String name; int age; GFG(String name, int age) { this .name = name; this .age = age; } public int getage() { return age; } public String getname() { return name; } public static void main(String[] args) { GFG ob[] = new GFG[ 4 ]; ob[ 0 ] = new GFG( “Aayush” , 14 ); ob[ 1 ] = new GFG( “Ravi” , 12 ); ob[ 2 ] = new GFG( “Sachin” , 19 ); ob[ 3 ] = new GFG( “Mohit” , 20 ); Arrays.sort(ob); for (GFG o : ob) { System.out.println(o.name + ” ” + o.age); } ArrayList objects = new ArrayList<>(); GFG newObject1 = new GFG( “Rohan Devaki” , 20 ); objects.add(newObject1); GFG newObject2 = new GFG( “Algorithammer” , 22 ); objects.add(newObject2); Collections.sort(objects); for (GFG o : objects) { System.out.format( “%s %d

” , o.name, o.age); } } @Override public int compareTo(GFG o) { if ( this .age > o.age) { return 1 ; } else if ( this .age < o.age) { return - 1 ; } else { return 0 ; } } } Output Ravi 12 Aayush 14 Sachin 19 Mohit 20 Rohan Devaki 20 Algorithammer 22

So you have finished reading the how to override compareto topic article, if you find this article useful, please share it. Thank you very much. See more: Override compareTo Java, Compareto java example, Method does not override method from its superclass compareto, compareTo in Java, compareTo int Java, Compareto generics java, Comparator Java, Override compareTo String java

Top 15 How To Override Compareto Trust The Answer

How to Override compareTo Method in Java? – GeeksforGeeks

comparable – How to override compareTo (Java) – Stack Overflow

How to Override compareTo Method in Java? – GeeksforGeeks

How to override compareTo method in Java – Example Tutorial

sorting – Is it possible to override String’s compareTo method in Java? – Stack Overflow

Override the CompareTo Method in Java | Delft Stack

Override the CompareTo Method in Java | Delft Stack

How to override compareTo method in Java – Example Tutorial

How to Override Equals, HashCode and CompareTo method in Java | Java67

Cómo anular compareTo (Java) – PeakU

Cómo anular compareTo (Java) – PeakU

Error 403 (Forbidden)

How to Override compareTo Method in Java?

How to override compareTo (Java)

How to Override compareTo Method in Java?

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