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Mod 3 Lesson 23 NYS 4th grade
See some more details on the topic explain your thinking or use division to answer the following here:
Lesson 23 Homework 4
1. Explain your thinking or use division to answer the following. a. Is 2 a factor of 72? b. Is 2 a factor of 73? c. Is 3 a factor of 72?
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Date Published: 1/30/2022
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Lesson 19 Homework 4.3
Explain your thinking or use division to answer the following. EXPLANATIONS WILL VARY a. Is 2 a factor of 72? YES (EVEN # b. Is 2 a factor of 73? NO (000#).
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Date Published: 11/29/2021
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Eureka Math Grade 4 Module 3 Lesson 23 Answer Key
Explain your thinking or use division to answer the following. a. Is 2 a factor of 84? Answer: Yes, 2 is a factor of 84,. Explanation:
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Date Published: 12/30/2021
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Lesson 6 Homework 574 – muhlsdk12.org
Find the value of each of the following. a. … Draw a set and shade to show your thinking. … Draw a picture to explain your thinking.
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Date Published: 2/4/2021
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Eureka Math Lesson 23 Homework 4.3 Answer Key
Explain your thinking or use division to answer the following. a. Is 2 a factor of 72? Answer: Yes, because 72 is even and 2 is a factor of all even numbers …
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Date Published: 12/12/2022
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Grade 4 Module 3 Lessons 1–38 Eureka Math™ Homework …
I can think, “4 times what number … Explain your thinking in words, and justify your … Solve the following expression using the standard algorithm, …
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Eureka Math Grade 4 Module 3 Lesson 23 Answer Key
Engage NY Eureka Math 4th Grade Module 3 Lesson 23 Answer Key
Eureka Math Class 4 Module 3 Lesson 23 Problem Set Answer Key
Question 1.
Justify your reasoning or use division to answer the following questions.
a. Is 2 a factor of 84?
Answers:
Yes, 2 is a factor of 84,
Explanation:
84 is an even number, 2 is a factor of every even number (2 x 42 = 84).
b. Is 2 a factor of 83?
Answers:
No, 2 is not a factor of 83,
Explanation:
83 is an odd number, 2 is not a factor of odd numbers, so 2 is not a factor of 83,
(2 x 41 = 82) and 82 + 1 = 83.
c. Is 3 a factor of 84?
Answers:
Yes, 3 is a factor of 84,
Explanation:
28
3| 84
-6
24
-24
0
So 3 is a factor of 84.
i.e. Is 2 a factor of 92?
Answers:
Yes, 2 is a factor of 92 and 92 is an even number,
Explanation:
46
2| 92
– 8th
12
-12
0
So 2 is a factor of 92.
e. Is 6 a factor of 84?
Answers:
Yes, 6 is a factor of 84 and 84 is an even number,
Explanation:
14
6| 84
– 6
24
-24
0
So 6 is a factor of 84.
f. Is 4 a factor of 92?
Answers:
Yes, 4 is a factor of 92,
Explanation:
23
4| 92
– 8th
12
-12
0
So 4 is a factor of 92.
G. Is 5 a factor of 84?
Answers:
No, 5 is not a factor of 84,
Explanation:
84 does not have a 5 or 0 in the ones place, all numbers that divide by 5 have a 5 or 0 in the ones place,
So 5 is not a factor of 84.
H. Is 8 a factor of 92?
Answers:
No, 8 is not a factor of 92,
Explanation:
11R4
8| 92
– 8th
12
-08
04
So 8 is not a factor of 92, the remainder is 4.
question 2
Use the associative law to find other factors of 24 and 36.
a. 24 = 12 × 2
= ( _4__ × 3) × 2
= __4_ × (3 × 2)
= _4__ × 6
= __24_
Answers:
24 = 12 x 2
= (4×3)x2
= 4 X (3 X 2)
= 4×6
= 24,
Explanation:
Use the associative property to find more factors of 24 as
24 = 12 x 2
= (4×3)x2
= 4 X (3 X 2)
= 4×6
= 24.
b. 36 = __9__ × 4
= ( __3__ × 3) × 4
= __3__ × (3 × 4)
= __3__ × 12
= _36__
Answers:
36 = 9×4
= (3×3)x4
= 3 X (3 X 4)
= 3 x 12
= 36,
Explanation:
Use the associative property to find other factors of 36 as
36 = 9×4
= (3×3)x4
= 3 X (3 X 4)
= 3 x 12
= 36.
question 3
In the lesson we used the associative property to show that if 6 is a factor then 2 and 3 are factors because 6 = 2 × 3.
Use the fact that 8 = 4 × 2 to show that 2 and 4 divide 56, 72, and 80.
56 = 8 × 7 72 = 8 × 9 80 = 8 × 10
Answers:
56 = 8×7
= (4×2)x7
= 4 X (2 X 7)
= 4 x 14
= 56,
72 = 8×9
= 8×9
= (4×2)x9
= 4 X (2 X 9)
= 4 x 18
= 72,
80 = 8 × 10
= 8×10
= (4×2)x10
= 4 X (2 X 10)
= 4×20
= 80,
Explanation:
Uses the fact that 8 = 4 × 2 to show that 2 and 4 divide 56, 72, and 80
56 = 8×7
= (4×2)x7
= 4 X (2 X 7)
= 4 x 14
= 56,
72 = 8×9
= 8×9
= (4×2)x9
= 4 X (2 X 9)
= 4 x 18
= 72,
80 = 8 × 10
= 8×10
= (4×2)x10
= 4 X (2 X 10)
= 4×20
= 80.
question 4
The first statement is wrong. The second statement is true. Explain why using words, pictures or numbers. If a number has 2 and 4 as factors, then it has 8 as a factor. If a number has 8 as a factor, then both 2 and 4 are factors.
Answers:
14
2|28
-2
08
-08
0
2 x 14 = 28,
7
4|28
-28
0
4 x 7 = 28,
3, R4
8|28
-24
04
28 has 2 and 4 as factors but not 8,
Explanation:
The first statement is wrong. The second statement is true. If a number has 2 and 4 as divisors, then it has 8 as divisors, and if a number has 8 as divisors, then both 2 and 4 are divisors,
14
2|28
-2
08
-08
0
2 x 14 = 28,
7
4|28
-28
0
4 x 7 = 28,
3, R4
8|28
-24
04
28 has 2 and 4 as factors but not 8, any number that can be exactly divided by 8 can also be divided by 2 and 4 instead, since 8 = 2 x 4,
Example: 8 x 5 = 40, (4 x 2) x 5 = 40.
Eureka Math Class 4 Module 3 Lesson 23 Exit Ticket Solution Key
Question 1.
Justify your reasoning or use division to answer the following questions.
a. Is 2 a factor of 34?
Answers:
Yes, 2 is a factor of 34,
Explanation:
34 is an even number, 2 is a factor of every even number
number, (2 x 17 = 34),
17R1
2| 34
– 2
14
-14
0
Yes, 2 is a factor of 34.
b. Is 3 a factor of 34?
Answers:
No, 3 is not a factor of 34,
Explanation:
11R1
3| 34
– 3
04
-03
01
So 3 is not a factor of 34, the remainder is 1.
c. Is 4 a factor of 72?
Answers:
Yes, 4 is a factor of 72,
Explanation:
18
4| 72
– 4
32
-32
0
So 4 is a factor of 72.
i.e. Is 3 a factor of 72?
Answers:
Yes, 3 is a factor of 72,
Explanation:
24
3| 72
– 6
12
-12
0
So 3 is a factor of 72.
question 2
Use the associative property to explain why the following statement is true. Any number that has 9 as a factor also has 3 as a factor.
Answers:
Any number that has 9 as a factor also has 3 as a factor because 3 x 3 = 9,
Explanation:
Suppose 9 is a factor of the number N.
This means that N is 9 times an integer M.
N = 9M, Since 9 = 3 × 3, we can also write N as N = 3 × 3 × M,
This means that N is an integer three times (3 × M).
So 3 is also a factor of N.
Eureka Math Class 4 Module 3 Lesson 23 Homework Answer Key
Question 1.
Justify your reasoning or use division to answer the following questions.
a. Is 2 a factor of 72?
Answers:
Yes, 2 is a factor of 72,
Explanation:
72 is an even number, 2 is a factor of every even number (2 x 36 = 72),
36
2| 72
– 6
12
-12
0
Yes, 2 is a factor of 72.
b. Is 2 a factor of 73?
Answers:
No, 2 is not a factor of 73,
Explanation:
73 is an odd number, 2 is a factor of every even number, not odd numbers, (2 x 36 = 72), 72 + 1 = 73
36 E1
2| 73
– 6
13
-12
1
No, 2 is not a factor of 73.
c. Is 3 a factor of 72?
Answers:
Yes, 2 is a factor of 72,
Explanation:
72 is an even number, 2 is a factor of every even number (2 x 36 = 72),
36
2| 72
– 6
12
-12
0
Yes, 2 is a factor of 72.
i.e. Is 2 a factor of 60?
Answers:
Yes, 2 is a factor of 60,
Explanation:
60 is an even number, 2 is a factor of every even number (2 x 30 = 60),
30
2| 60
– 60
0
Yes, 2 is a factor of 60.
e. Is 6 a factor of 72?
Answers:
Yes, 6 is a factor of 72,
Explanation:
(6 x 12 = 72),
12
6| 72
– 6
12
-12
0
Yes, 6 is a factor of 72.
f. Is 4 a factor of 60?
Answers:
Yes, 4 is a factor of 60,
Explanation:
60 is an even number, 4 is a factor of 60 (4 x 15 = 60),
fifteen
4|60
-4
20
-20
0
Yes, 4 is a factor of 60.
G. Is 5 a factor of 72?
Answers:
No, 5 is not a factor of 72,
Explanation:
72 is an even number, 72 does not have a 5 or 0 in the ones place, all numbers that have 5 as a factor have a 5 or 0 in the ones place,
So 5 is not a factor of 72.
14 E 2
5|72
-5
22
-20
2
No, 5 is not a factor of 72.
H. Is 8 a factor of 60?
Answers:
No, 8 is not a factor of 60,
Explanation:
60 is an even number, 8 is not a factor of 60,
(8 x 7 = 56, remainder 4),
7R4
8|60
-56
04
No, 8 is not a factor of 60.
question 2
Use the associative law to find more factors of 12 and 30.
a. 12 = 6 × 2
= ( __3_ × 2) × 2
= _3__ × (2 × 2)
= _3__ × _4__
= _12__
Answers:
12 = 6×2
= (3×2)x2
= 3 X (2 X 2)
= 3×4
= 12,
Explanation:
Use the associative property to find other factors of 12 as
12 = 6×2
= (3×2)x2
= 3 X (2 X 2)
= 3×4
= 12.
b. 30 = __6__ × 5
= ( __2__ × 3) × 5
= __2__ × (3 × 5)
= __2__ × 15
= __30__
Answers:
30 = 6 x 5
= (2×3)x5
= 2 X (3 X 5)
= 2 x 15
= 30,
Explanation:
Use the associative property to find other factors of 30 as
30 = 6 x 5
= (2×3)x5
= 2 X (3 X 5)
= 2 x 15
= 30.
question 3
In the lesson we used the associative property to show that if 6 is a factor then 2 and 3 are factors because 6 = 2 × 3.
Use the fact that 10 = 5 × 2 to show that 2 and 5 divide 70, 80, and 90.
70 = 10 × 7 80 = 10 × 8 90 = 10 × 9
Answers:
70 = 10 x 7
= (5×2)x7
= 5x (2×7)
= 5 x 14
= 70,
80 = 10×8
= 10×8
= (5×2)x8
= 5x (2×8)
= 5×16
= 80,
90 = 10 × 9
= 10 x 9
= (5×2)x9
= 5x(2×9)
= 5×18
= 90,
Explanation:
Uses the fact that 10 = 5 × 2 to show that 2 and 5 are factors of 70, 80, and 90
70 = 10 x 7
= (5×2)x7
= 5x (2×7)
= 5 x 14
= 70,
80 = 10×8
= 10×8
= (5×2)x8
= 5x (2×8)
= 5×16
= 80,
90 = 10 × 9
= 10 x 9
= (5×2)x9
= 5x(2×9)
= 5×18
= 90.
question 4
The first statement is wrong. The second statement is true.
Explain why using words, pictures or numbers. If a number has 2 and 6 as a divisor, then it has 12 as a divisor. If a number has 12 as a factor, then both 2 and 6 are factors.
Answers:
9
2|18
-18
0
2 x 9 = 18,
3
6|18
-18
0
6 x 3 = 18,
1, R6
12|18
– 12
06
18 has 2 and 6 as factors but not 12,
Explanation:
The first statement is wrong. The second statement is true. If a number has 2 and 6 as a divisor, then it has 12 as a divisor, and if a number has 12 as a divisor, then both 2 and 6 are divisors,
9
2|18
-18
0
2 x 9 = 18,
3
6|18
-18
0
6 x 3 = 18,
1, R6
12|18
– 12
06
18 has 2 and 6 as factors but not 12, any number that can be exactly divided by 12 can also be divided by 2 and 6 instead since 12 = 2 x 6.
Eureka Math Lesson 23 Homework 4.3 Answer Key
The Eureka Maths Lesson 23 Homework 4.3 Solution Key is below. Just try it to find out how many questions you can answer correctly. If you get the wrong answer, you can easily correct it. Make sure you not only check the answer but also understand it as that is the most important thing.
Justify your reasoning or use division to answer the following questions.
a. Is 2 a factor of 72?
Answer: Yes, because 72 is even and 2 divides all even numbers.
b. Is 2 a factor of 73?
Answer: No, because 73 is odd and 2 is not an odd factor.
c. Is 3 a factor of 72?
Answer: Yes, because 3 x 24 = 72.
i.e. Is 2 a factor of 60?
Answer: Yes, because 60 is even.
e. Is 6 a factor of 72?
Answer: Yes, because 6 x 12 = 72.
f. Is 4 a factor of 60?
Answer: Yes, because 4 x 15 = 60.
G. Is 5 a factor of 72?
Answer: No, because 72 doesn’t have a 5 or 0 in the ones place.
H. Is 8 a factor if 60?
Answer: No, because there is a remainder.
2. Use the associative law to find more factors of 12 and 30.
a. 12 = 6 x 2 = (2 x 3) x 2 = 2 x (3 x 2) = 12
b. 30 = 6 x 5 = (2 x 3) x 5 = 2 x (3 x 5) = 2 x 15 = 30
3. In the lesson we used the associative law to show that 2 and 3 are factors if 6 is a factor, because 6 = 2 x 3. Use the fact that 10 = 5 x 2 to show that that 2 and 5 are factors of 70, 80 and 90.
Answers:
70 – 10 x 7 = (2 x 5) x 7 = 2 x (5 x 7) = 2 x 35 = 70
80 = 10 x 8 = (2 x 5) x 8 = 2 x (5 x 8) = 2 x 40 = 80
90 = 10 x 9 = (2 x 5) x 9 = 2 x (5 x 9) = 2 x 45 = 90
4. The first statement is wrong. The second statement is true. Explain why you are using words, pictures or numbers.
a. If a number has 2 and 6 as a divisor, then it has 12 as a divisor.
b. If a number has 12 as a factor, then both 2 and 6 are factors.
Answers:
A is false because 2 and 6 are factors of 18, but 12 is not a factor of 18.
B is true because if 12 is a factor then 2 and 6 must also be factors since 12 = 2 x 6.
If the result isn’t that satisfying, don’t get discouraged and keep practicing until you surpass it.
In addition to the answer key from Eureka Math Lesson 23 Homework 4.3, you may also need the answer key from the previous lesson. For everyone who really wants to know the Eureka Maths Lesson 22 Homework Solution Key, here is everything for you:
Write down the factors of the given numbers as sets of multiplication and as a list in order from smallest to largest. Classify each as Prime (P) or Composite (C). The first problem is solved for you:
Multiplication sets Factors P or C a. 8 1 x 4 = 8 2 x 4 = 8 The factors of 8 are: 1, 2, 4, and 8. C b. 10 1 x 10 = 10 2 x 5 = 10 The factors of 10 are: 1, 2, 5, 10. C c. 11 1 x 11 = 11 The factors of 11 are: 1 and 11. P d. 14 1 x 14 = 14 2 x 7 = 14 The factors of 14 are: 1, 2, 7, and 14. C e. 17 1 x 17 = 17 The factors of 17 are: 1 and 17. P f. 20 1 x 20 = 20 2 x 10 = 20 4 x 5 = 20 The factors of 20 are: 1, 2, 4, 5, 10 and 20.Cg. 22 1 x 22 = 22 2 x 11 = 22 The factors of 22 are: 1, 2, 11 and 22. C h. 23 1 x 23 = 23 The factors of 23 are: 1 and 23. C i. 25 1 x 25 = 25 5 x 5 = 25 The factors of 25 are: 1, 5, and 25. C j. 26 1 x 26 = 26 2 x 13 = 26 The factors of 26 are: 1, 2, 13, and 26. C k. 27 1 x 27 = 27 3 x 9 = 27 The factors of 27 are: 1, 3, 9, and 27. C l. 28 1 x 28 = 28 2 x 14 = 28 4 x 7 = 28 The factors of 28 are: 1, 2, 4, 7, 14, and 28. C
Find all the factors for the following numbers and classify them as prime or composite. Explain your classification of each as prime or composite.
Prime:
Factor pairs for 19 1 19
There are only 2 factors.
Composed:
Pairs of factors for 21 1 21 3 7
There are more than 2 factors.
Composed:
Pairs of factors for 24 1 24 2 12 3 8 4 6
There are more than 2 factors.
Bryan says that only even numbers are composite.
a. List all odd numbers less than 20 in numerical order.
Answer: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19
b. Use your list to show Bryan’s claim is wrong.
Answer: 9 and 15 are odd, but also compound.
Julie has 27 grapes that she needs to split evenly among 3 friends. She thinks there will be no leftovers. Use your knowledge of factor pairs to explain if Julie is correct.
Answer: Since 3 x 9 = 27, it can be concluded that there will be no remainders.
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