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A standing wave in a string 35 cm long has a total of six nodes
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Measurement Word Problem Example
String A is 35 centimeters long. String B is 5 times as long as String A. Both are necessary to create a decorative bottle. Find the total length of string …
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Date Published: 7/9/2021
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String A is 35 centimeters long.string B is 5 times … – Brainly.com
String A is 35 centimeters long.string B is 5 times as long as string a .both are necessary o create a decorative bottle. Find the total length of string needed …
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Date Published: 1/15/2022
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{:(“Column A” , “A piece of string 35 cm long is cut”,”ColumnB …
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A standing wave in a string 35 cm long has a total of … – Toppr
Click here to get an answer to your question ✍️ A standing wave in a string 35 cm long has a total of six nodes including those at the ends.
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String a is 35 centimeters long. String b is 5 times … – Numerade
String a is 35 centimeters long. String b is 5 times long as string a. Both are necessary to create a decorative bottle. Find the total length of string needed …
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Date Published: 6/7/2021
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A standing wave in a string 35 cm long has a total of six nodes …
A standing wave in a string 35 cm long has a total of six nodes including those at the ends Hence wavelength of the standing wave is A 58 cm B 46 cm C 104 …
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Date Published: 7/17/2021
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SOLVED:String a is 35 centimeters long. String b is 5 times long as string a. Both are necessary to create a decorative bottle. Find the total length of string needed for 17 identical decorative bottl
video transcript
Here we have five and 14 foot long wire cut into seven pieces. So that means I want to do 5 1/4 divided by seven. So turn us into an improper fraction. Which gets me 21/4 times the reciprocal which is 1/7. And we can multiply these by seven to get three and one and one right across and we get a 3/4 feature so each piece is 3/4 feats.
A standing wave in a string 35 cm long has a total class 12 physics CBSE
A notice:
Since there are six nodes in total, we can say that there are five segments between the nodes. The distance between two nodes is half the wavelength for standing waves on the string. Here the formula for calculating the length of a string is used.
Formula used:
The length of a string is given by,
\[L=\left( n-1 \right)\times \lambda /2\]
Where n is the number of nodes and \[\lambda \] is the wavelength.
Full answer:
given,
L=35cm
n=6
Substituting these values into the formula for length, we get
\[\begin{collected}
& L=\left( n-1 \right)\times \lambda /2 \\
& 35=\left( 6-1 \right)\times \lambda /2 \\
\end{collected}\]
Now let’s simplify this to find the value of \[\lambda \] as follows:
\[\begin{collected}
& 35=\left( 6-1 \right)\times \lambda /2 \\
& 35=5\times \lambda /2 \\
& \lambda =\dfrac{35\times 2}{5} \\
& λ =14 \\
\end{collected}\]
Therefore, the wavelength of the standing wave is 14 cm.
The answer is option D.
Note:
We should not be confused between the number of nodes and the segments between nodes. The wavelength is calculated using the sections between nodes. For example, a string on an instrument is clamped at both ends, and therefore a string must have a knot at each end when it vibrates. However, for a fundamental harmonic, the length is computed as \[\lambda /2\]. This is only possible if we consider the section between the two nodes and not the number of nodes. The wavelength has the same unit as the given length, i.e. cm.
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