당신은 주제를 찾고 있습니까 “this decimal constant is unsigned only in iso c90 – Problems on min-max normalization, z-score normalization and Normalization by decimal scaling“? 다음 카테고리의 웹사이트 https://chewathai27.com/you 에서 귀하의 모든 질문에 답변해 드립니다: https://chewathai27.com/you/blog. 바로 아래에서 답을 찾을 수 있습니다. 작성자 kuriosity stream 이(가) 작성한 기사에는 조회수 17,440회 및 좋아요 150개 개의 좋아요가 있습니다.
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d여기에서 Problems on min-max normalization, z-score normalization and Normalization by decimal scaling – this decimal constant is unsigned only in iso c90 주제에 대한 세부정보를 참조하세요
Solved example Problem on min-max normalization, z-score normalization and Normalization by decimal scaling
this decimal constant is unsigned only in iso c90 주제에 대한 자세한 내용은 여기를 참조하세요.
Warning: this decimal constant is unsigned only in ISO C90
C90 does not have the long long type, which is the reason why it handles such numbers differently than C99. … FYI: The correct answer is found …
Source: stackoverflow.com
Date Published: 3/23/2021
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this decimal constant is unsigned only in ISO C90″ solution
The constant value in C language is a 32-bit signed integer by default. Since 2394967295 cannot be represented by a 32-bit signed integer number, an alarm will …
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Date Published: 11/6/2021
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warning: this decimal constant is unsigned only in ISO C90
Filing bug on this GCC build warnings: { js/src/jsapi-tests/testIndexToString.cpp:46:5: warning: this decimal constant is unsigned only in ISO C90 …
Source: bugzilla.mozilla.org
Date Published: 4/14/2021
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warning: decimal constant is unsigned only in ISO C90 …
warning: decimal constant is unsigned only in ISO C90 [enabled by default]. #include
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c – Warning: this decimal constant is unsigned only in ISO C90
The rules for the types of decimal integer constants changed between the 1990 and 1999 editions of the ISO C standard. In the 1990 version, …
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warning: this decimal constant is unsigned only in ISO C90
warning: this decimal constant is unsigned only in ISO C90. Regarding the large integer constants in the C language-by the rogue Tusky, I discovered this …
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this decimal constant is unsigned only in ISO C90 – Katastros
warning: this decimal constant is unsigned only in ISO C90. View ImageRegarding the large integer constants in the C language-by the rogue Tusky found this …
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Date Published: 11/11/2022
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this decimal constant is unsigned only in ISO C90 – Fear Cat
warning: this decimal constant is unsigned only in ISO C90. Author: Wang Yun Maigo link: https://www.zhihu.com/question/22346138/answer/21084638
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this decimal constant is unsigned only in ISO C90
decimal constant is unsigned only in ISO C90 ? I think -2147483648 is the min number for 32 bit signed integer. #include
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Date Published: 8/9/2021
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Can’t get rid of “this decimal constant is unsigned only in ISO …
unsigned hash = 2166136261u; // note the u. You need a suffix u to signify this is an unsigned number. Without the u suffix it will be a …
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주제와 관련된 이미지 this decimal constant is unsigned only in iso c90
주제와 관련된 더 많은 사진을 참조하십시오 Problems on min-max normalization, z-score normalization and Normalization by decimal scaling. 댓글에서 더 많은 관련 이미지를 보거나 필요한 경우 더 많은 관련 기사를 볼 수 있습니다.
주제에 대한 기사 평가 this decimal constant is unsigned only in iso c90
- Author: kuriosity stream
- Views: 조회수 17,440회
- Likes: 좋아요 150개
- Date Published: 2019. 2. 26.
- Video Url link: https://www.youtube.com/watch?v=_PF6lTxaTK4
Warning: this decimal constant is unsigned only in ISO C90
The rules for the types of decimal integer constants changed between the 1990 and 1999 editions of the ISO C standard.
In the 1990 version, an unsuffixed decimal integer constant’s type is the first of int , long int , or unsigned long int in which its value can be represented. (C90 had no long long or unsigned long long type).
In the 1999 and 2011 versions, its type is one of int , long int , long long int ; it’s never of any unsigned type.
The type of a particular constant (such as 2147483648 ) will vary depending on the ranges of the integer types for the compiler you’re using. If your compiler’s long type happens to be 32 bits, then 2147483648 will be of type unsigned long if your compiler uses C90 rules, or of type long long if it uses C11 rules ( long long is guaranteed to be at least 64 bits). The compiler is warning you about this.
You can add suffixes to specify the type of a constant — but there’s no suffix for plain signed int . You can add U for unsigned int , L for long , UL for unsigned long, and so forth.
It’s important to keep in mind that -2147483648 is not an integer constant; rather 2147483648 by itself is an integer constant, and -2147483648 is an expression that applies a unary minus operator to that constant. Under C90 rules, if the constant is of type unsigned long , that’s an unsigned unary minus, which under the rules of unsigned arithmetic yields the value 2147483648 . Under C99 or C11 rules, 2147483648 is likely to be of type (signed) long long , and negating it yields -2147483648 , also of type long long .
You’ll sometimes see code that uses (-2147483647 – 1) to avoid this problem; given a 32-bit int , 2147483647 is of type int and the result of the expression yields the expected int value without overflow.
Of course if your compiler has different sizes for the integer types, this can become even more complicated.
“Warning: this decimal constant is unsigned only in ISO C90” solution
1. Problem description: warning: this decimal constant is unsigned only in ISO C90
2. When the program is compiled: warning: this decimal constant is unsigned only in ISO C90
condensed code is as follows: warning: this decimal constant is unsigned only in ISO C902. When the program is compiled: warning: this decimal constant is unsigned only in ISO C90condensed code is as follows:
# include < stdio.h >
int main( int argc, char * argv[])
{
unsigned int i = 4286545791; printf( “%d
” ,i); return 0 ; }
3. When compiling, the GCC compiler will throw the following warning: 3. When compiling, the GCC compiler will throw the following warning:
$ gcc -o test test.c
test.c: In function’main’ :
test.c:4: warning : this decimal constant is unsigned onlIy in ISO C90
4. The description of c standard:
The C90 rule that the default type of a decimal integer constant is either int, long, orunsigned long, depending on which type is large enough to hold the value without overflow,simplifies the use of constants. The choices in C99 are int, long and long long.C89 added the suffixes U and u to specify unsigned numbers. C99 adds LL to specify longlong.Unlike decimal constants, octal and hexadecimal constants too large to be ints are typed asunsigned int if within range of that type, since it is more likely that they represent bitpatterns or masks, which are generally best treated as unsigned, rather than “real” numbers.Little support was expressed for the old practice of permitting the digits 8 and 9 in an octalconstant, so it was dropped in C89.A proposal to add binary constants was rejected due to lack of precedent and insufficient utility.Despite a concern that a “lower-case-l” could be taken for the numeral one at the end of anumeric literal, the C89 Committee rejected proposals to remove this usage, primarily on the
grounds of sanctioning existing practice.
The constant value in C language is a 32-bit signed integer by default. Since 2394967295 cannot be represented by a 32-bit signed integer number, an alarm will be generated, that is, the problem usually occurs when the default type is not stored enough.
5. Solution:
1 Add a U logo after the constant, if it is long or longlong type, add UL or ULL, such as 428655791U for type coercion, so that it will not alarm
2 Use hexadecimal numbers, such as 0xFFFFFFFF
3 Use gcc -std= C99 is compiled with the 99 standard
Warning: this decimal constant is unsigned only in ISO C90
The rules for the types of decimal integer constants changed between the 1990 and 1999 editions of the ISO C standard.
In the 1990 version, an unsuffixed decimal integer constant’s type is the first of int , long int , or unsigned long int in which its value can be represented. (C90 had no long long or unsigned long long type).
In the 1999 and 2011 versions, its type is one of int , long int , long long int ; it’s never of any unsigned type.
The type of a particular constant (such as 2147483648 ) will vary depending on the ranges of the integer types for the compiler you’re using. If your compiler’s long type happens to be 32 bits, then 2147483648 will be of type unsigned long if your compiler uses C90 rules, or of type long long if it uses C11 rules ( long long is guaranteed to be at least 64 bits). The compiler is warning you about this.
You can add suffixes to specify the type of a constant — but there’s no suffix for plain signed int . You can add U for unsigned int , L for long , UL for unsigned long, and so forth.
It’s important to keep in mind that -2147483648 is not an integer constant; rather 2147483648 by itself is an integer constant, and -2147483648 is an expression that applies a unary minus operator to that constant. Under C90 rules, if the constant is of type unsigned long , that’s an unsigned unary minus, which under the rules of unsigned arithmetic yields the value 2147483648 . Under C99 or C11 rules, 2147483648 is likely to be of type (signed) long long , and negating it yields -2147483648 , also of type long long .
You’ll sometimes see code that uses (-2147483647 – 1) to avoid this problem; given a 32-bit int , 2147483647 is of type int and the result of the expression yields the expected int value without overflow.
Of course if your compiler has different sizes for the integer types, this can become even more complicated.
warning: this decimal constant is unsigned only in ISO C90
Regarding the large integer constants in the C language-by the rogue Tusky, I discovered this problem when compiling the program before: warning: this decimal constant is unsigned only in ISO C90. I
found a solution and recorded:
1 Add a UL after the constant Logo, or ULL, such as 4294967295UL, so it won’t alarm.
2 Use hexadecimal numbers, such as 0xFFFFFFFF.
3 Use gcc -std=c99 to compile with the 99 standard and
see what the c standard says:
The C90 rule that the default type of a decimal integer constant is either int, long, or
unsigned long, depending on which type is large enough to hold the value without overflow,
simplifies the use of constants. The choices in C99 are int, long and long long.
C89 added the suffixes U and u to specify unsigned numbers. C99 adds LL to specify long
long.
Unlike decimal constants, octal and hexadecimal constants too large to be ints are typed as
unsigned int if within range of that type, since it is more likely that they represent bit
patterns or masks, which are generally best treated as unsigned, rather than “real” numbers.
Little support was expressed for the old practice of permitting the digits 8 and 9 in an octal
constant, so it was dropped in C89.
A proposal to add binary constants was rejected due to lack of precedent and insufficient utility.
Despite a concern that a “lower-case-l” could be taken for the numeral one at the end of a
numeric literal, the C89 Committee rejected proposals to remove this usage, primarily on the
grounds of sanctioning existing practice. Understood
, this warning appears, in fact, gcc reminds you to upgrade your compilation options. But the safest is to use hexadecimal, or add UL or ULL such instructions.
warning: this decimal constant is unsigned only in ISO C90
View Image
Regarding the large integer constants in the C language-by the rogue Tusky found this problem when compiling the program before: warning: this decimal constant is unsigned only in ISO C90
1 Add a UL logo or ULL after the constant, such as 4294967295UL, so that it will not alarm.
2 Use hexadecimal numbers, such as 0xFFFFFFFF.
3 Use gcc -std=c99 to compile with the 99 standard
View Image
warning: this decimal constant is unsigned only in ISO C90
Very interesting question.
-2147483648 is not a numeric constant, but an expression, which is 2147483648 plus a unary operator “-” in front of the numeric constant.
And 2147483648 itself is beyond the scope of the int type, and you did not specify its type with a suffix (L, UL, etc.), so it will lead to undefined behavior.
The following are several possible evaluation processes of the expression -2147483648 that I thought of:
1) 2147483648 exceeds the range of the int type, and becomes -2147483648 of the int type after overflow. Calculating the opposite of this value, the result 2147483648 is out of the range of the int type, and the overflow becomes -2147483648 of the int type. The result was just right.
2) 2147483648 is out of the range of the int type and is cast into an unsigned int type 2147483648. Calculating the opposite of this value, the result -2147483648 is out of the range of unsigned int type, and it overflows to become unsigned int type 2147483648. The result was a negative sign.
3) 2147483648 exceeds the range of int type and is cast into long int type (64-bit) 2147483648. Inverting this value, the result -2147483648 is still in the range of long int type. The result was just right.
The above three cases are only “possible”, which depends on the compiler. As a programmer, you should not rely on this undefined behavior.
Go back to your program.
4) int a = -2147483648; In this sentence, no matter which of the above three evaluation processes is passed through -2147483648, the final result will be cast into int and assigned to a. In this way, the value of a must be -2147483648. So the calculation result of a/b is correct.
5) And printf(“%ld
“, -2147483648/1000000000); This sentence, from your compiler output (enabled), should be 2147483648 as an unsigned int constant, that is, the second Kind of evaluation process. So the result was reversed.
Bonus:
Since the expression -2147483648 will cause undefined behavior, what should I do when the value -2147483648 is really used in the program? There are two ways:
a) Write as (int)-2147483648. From the analysis of (4) above, the value must be negative after cast into int type. However, although the result is correct, it causes undefined behavior in the process and is not recommended.
b) Use INT_MIN. The definition of this macro is as follows:
#define INT_MIN (-2147483647 – 1)
This expression will not cause undefined behavior, and the result is indeed -2147483648.
What’s the meaning of this warning: this decimal constant is unsigned only in ISO C90
Post by Nan Li
Hello,
Can any one help me understand the meaning of this warning: this
decimal constant is unsigned only in ISO C90 ? I think -2147483648 is
the min number for 32 bit signed integer.
#include
static const int32_t value = -2147483648;
warning: this decimal constant is unsigned only in ISO C90
gcc version 4.0.2 20051125
Thanks !
Hello,Can any one help me understand the meaning of this warning: thisdecimal constant is unsigned only in ISO C90 ? I think -2147483648 isthe min number for 32 bit signed integer.#include static const int32_t value = -2147483648;warning: this decimal constant is unsigned only in ISO C90gcc version 4.0.2 20051125Thanks !
—
Jack Klein
Home: http://JK-Technology.Com
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Can’t get rid of “this decimal constant is unsigned only in ISO C90” warning
I’m using the FNV hash as a hashing algorithm on my Hash Table implementation but I’m getting the warning in the question title on this line:
unsigned hash = 2166136261;
I don’t understand why this is happening because when I do this:
printf(“%u “, UINT_MAX); printf(“2166136261 “);
I get this:
4294967295 2166136261
Which seems to be under the limits of my machine…
Why do I get the warning and what are my options to get rid of it?
See Question&Answers more detail: os
키워드에 대한 정보 this decimal constant is unsigned only in iso c90
다음은 Bing에서 this decimal constant is unsigned only in iso c90 주제에 대한 검색 결과입니다. 필요한 경우 더 읽을 수 있습니다.
이 기사는 인터넷의 다양한 출처에서 편집되었습니다. 이 기사가 유용했기를 바랍니다. 이 기사가 유용하다고 생각되면 공유하십시오. 매우 감사합니다!
사람들이 주제에 대해 자주 검색하는 키워드 Problems on min-max normalization, z-score normalization and Normalization by decimal scaling
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Problems #on #min-max #normalization, #z-score #normalization #and #Normalization #by #decimal #scaling
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주제에 대한 기사를 시청해 주셔서 감사합니다 Problems on min-max normalization, z-score normalization and Normalization by decimal scaling | this decimal constant is unsigned only in iso c90, 이 기사가 유용하다고 생각되면 공유하십시오, 매우 감사합니다.
