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- Summary of article content: Articles about Loading… There are n people standing in line to buy show tickets.Due to high demand, the venue sells tickets according to the following rules:. …
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Hackerrank – Code Interview Note
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- Summary of article content: Articles about Hackerrank – Code Interview Note Buying show ticket · Dive array by index p. · In first half, count the number only it is greater than ticket[i], otherwise return p · In second half the same, … …
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Attention Required! | Cloudflare
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javascript – How to optimise algorithm for Buying Show Tickets when using nodeJS – Stack Overflow
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- Summary of article content: Articles about javascript – How to optimise algorithm for Buying Show Tickets when using nodeJS – Stack Overflow Given a list of ticket buyers with their numbers of desired tickets, determine how long it will take Jesse to purchase his tickets. Jesse’s … …
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Twitter 实习OA – Interview – 1024 BBS
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- Summary of article content: Articles about Twitter 实习OA – Interview – 1024 BBS 总共4题，用 Hackerrank. … There are n people standing in line to buy show tickets.Due to high demand, the venue sells tickets according to … …
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Question 1 : https://leetcode.com/discuss/interview-question/375258/Twitter-or-OA-2019-or-Game-Events
Question 2 : https://leetcode.com/discuss/interview-question/374440/Twitter-or-OA-2019-or-Weird-F… - Table of Contents:
推特 OA Buying Show Tickets 地里没有的一道题|一亩三分地海外面经版
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Access to this page has been denied.
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- Summary of article content: Articles about Access to this page has been denied. language -> python or c/c++ or js. Show transcribed image text … Example n = 3 tickets = [1, 2, 5) There are 3 buyers needing 1, 2 and 5 tickets each. …
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buying show tickets twitter hackerrank
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buying show tickets twitter hackerrank
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- Summary of article content: Articles about buying show tickets twitter hackerrank Buying Show TicketsAlex plans on visiting the museum and is at the counter to purchase passes for the same. The administrators have deced not to sell … …
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Access Denied
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- Summary of article content: Articles about Access Denied Ticket · There are people at the railway station, and each one wants to buy a ticket to go to one of · There are ticket windows from which tickets can be … …
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How to optimise algorithm for Buying Show Tickets when using nodeJS
I was giving test on some portal where question was as follows:
A line has formed to buy tickets for a concert. In order to delay a shortage caused by brokers buying large blocks of tickets, venue management has decided to sell only one ticket at a time. Buyers have to to wait through line again if they want to buy more tickets. Jesse is standing in line and has a number of tickets to purchase. Given a list of ticket buyers with their numbers of desired tickets, determine how long it will take Jesse to purchase his tickets. Jesse’s position in line will be stated, and each transaction takes 1 unit of time. For your purposes, no time is spent moving to the back of the line. For example, if the zero indexed array of ticket requirements, tickets = [1, 2, 5] , and Jesse’s position p = 1, the first five seconds of ticket sales look like this:
Function Description
Complete the function waitingTime in the editor below. The function must return an integer representing the units of time it takes Jesse to purchase his desired number of tickets.
waitingTime has the following parameter(s):
tickets[tickets[0],…tickets[n-1]]: an array of tickets desired by each person at position tickets[i] p: Jesse’s position in line
Constraints
1 <= n <= 10 5 1 <= tickets[i] <= 10 9 , where 0 <= i < n. , where 0 <= i < n. 0 <= p < n Sample Input 0 5 2 6 3 4 5 2 Sample Output 0 12 It took a total of 12 units of time to purchase 2 tickets. My solution was as follows: function waitingTime(tickets, p) { var totalTime = 0, l = tickets.length, frontPersonStatus; while(true) { if(p === 0 && tickets[0] === 1 && ++totalTime) break; frontPersonStatus = tickets.shift() - 1; frontPersonStatus !== 0 ? (tickets[tickets.length] = frontPersonStatus) : l -= 1; totalTime++; p = p === 0 ? l - 1 : p - 1; } return totalTime; } but it runs for some test cases after that it goes all other test cases fails and says terminated due to timeout.b So I think there must be some more optimised solution then this
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