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Contents
How many grams are in 5 mg of aspartame?
Mass of aspartame = 5 mg = 0.005 grams. Also molar mass of aspartame = 294.3 grams.
How many molecules are in a mole of aspartame?
Mall and one mole of aspartame contains 6.0 22 into 10 power 23 molecules.
How many molecules are in 10g of aspartame?
Conclusion: With 10g of Aspartame there is 0.03mol .
How many molecules is 5 grams?
01 +15.99. Therefore molecular mass of water (M) is equal to 18,01. So in 5g sample of water there is 1.67 x 1023 water molecules.
How many moles are in a MG?
For example, one atom of magnesium weighs 24.31 amu (atomic mass units). However, one mole of magnesium weighs 24.31 g.
How many molecules are in a mole?
6.022 x 1023 hydrogen atoms represent one mole of hydrogen. 6.022 x 1023 water molecules represent one mole of water.
How many hydrogen atoms are present in 1mg of Aspartame?
Therefore for every 1 mole of Aspartame we have 18 moles of Hydrogen atoms.
How do I calculate moles?
- The formula for the number of moles formula is expressed as.
- Given.
- Number of moles formula is.
- Number of moles = Mass of substance / Mass of one mole.
- Number of moles = 95 / 86.94.
How many particles are there in 1.43 g of a molecular compound with a gram molecular mass of 233 g?
| Question | Answer |
|---|---|
| Find the mass, in grams, of 1.00 x 1023 molecules of N2 | 4.65 g |
| How many particles are there in 1.43 g of a molecular compound with a gram molecular mass of 233 g? | 3.69 x 10 |
| What is the mass in grams of 1.56 moles of aspartame? | 3.4 x 10^-2 moles |
What is the mass of 1 mole of Aspartame?
What is the gram formula mass of Aspartame?
| PubChem CID | 134601 |
|---|---|
| Molecular Formula | C14H18N2O5 |
| Synonyms | aspartame 22839-47-0 Nutrasweet Asp-phe-ome Asp-Phe methyl ester More… |
| Molecular Weight | 294.30 |
| Dates | Modify 2022-07-16 Create 2005-06-24 |
How do you calculate molecules?
Calculate he number of moles you have by taking the Mass / molar mass. if you have 1000 grams ; then 1,000 g / 151.001 g/mol = X g moles. Then multiply by Avogadros # = 6.022140857 × 10^23 molecules per g mole. The result is the # of molecules of MnSO4.
How many molecules are in a gram?
The definition of Avogadro’s number of 6.022 × 1023/mole is the number of atoms or molecules per one gram atomic weight.
What is the gram formula mass of Aspartame?
| PubChem CID | 134601 |
|---|---|
| Molecular Formula | C14H18N2O5 |
| Synonyms | aspartame 22839-47-0 Nutrasweet Asp-phe-ome Asp-Phe methyl ester More… |
| Molecular Weight | 294.30 |
| Dates | Modify 2022-07-16 Create 2005-06-24 |
What is the mass in grams of 1.56 mol Aspartame?
Conclusion: 1.56mol of Aspartame has a mass of 459.17g.
What is the molar mass of Aspartame?
Why is mole concept important?
The concept of mole is very important in chemistry, almost all the calculations, at least in general chemistry, involve this concept. Here you will able to count atoms, molecules, and ions through the vehicle of mole. molar mass of C-12 because it represents the mass of one mole of C-12.
How many molecules are in 5 mg of aspartame? | Socratic
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- Summary of article content: Articles about How many molecules are in 5 mg of aspartame? | Socratic Aspartame has the chemical formula C14H18N2O5 , and its molar mass is calculated to be 294.30 g/mol . Let’s convert the given mass ( 5 mg ) … …
- Most searched keywords: Whether you are looking for How many molecules are in 5 mg of aspartame? | Socratic Aspartame has the chemical formula C14H18N2O5 , and its molar mass is calculated to be 294.30 g/mol . Let’s convert the given mass ( 5 mg ) … 1 xx 10^19 “molecules C”_14″H”_18″N”_2″O”_5 We’re asked to find the number of molecules of a given mass of a substance. We can do this using the molar mass of the substance and Avogadro’s constant, 6.022 xx 10^23. Aspartame has the chemical formula “C”_14″H”_18″N”_2″O”_5, and its molar mass is calculated to be 294.30 “g/mol”. Let’s convert the given mass (5 “mg”) to moles of aspartame: 5cancel(“mg”)((1cancel(“g”))/(10^3cancel(“mg”)))((1color(white)(l)”mol”)/(294.30cancel(“g”))) = color(red)(1.70 xx 10^-5 color(red)(“mol aspartame” Using Avogadro’s constant, we can convert this value to molecules as so: color(red)(1.70xx10^-5)cancel(color(red)(“mol”))((6.022xx10^23color(white)(l)”molecules”)/(1cancel(“mol”))) = color(blue)(1 xx 10^19 color(blue)(“molecules aspartame” which I’ll leave at one significant figure, as allowed by the problem..
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SOLVED:What is the mass in grams of [.56 moles of aspartame?
How many molecules are in 0.005g of aspartame?
How many atoms of nitrogen are in [.2 grams of aspartame?
How many moles in 28 grams of UOz
What is the mass of 5 moles of curious chloride (CmCl;)
13. Find the numbcr of moles of chlorous acid (HCIOz) in 452 g of chlorous acid.
14, Find the grams in [.26 x 10-4 mol of acetic acid (HCH;COO)
15 . Find the mass in 2.6 mol of CxH,z (which is called windowpane).
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- Summary of article content: Articles about SOLVED:What is the mass in grams of [.56 moles of aspartame?
How many molecules are in 0.005g of aspartame?
How many atoms of nitrogen are in [.2 grams of aspartame?
How many moles in 28 grams of UOz
What is the mass of 5 moles of curious chloride (CmCl;)
13. Find the numbcr of moles of chlorous acid (HCIOz) in 452 g of chlorous acid.
14, Find the grams in [.26 x 10-4 mol of acetic acid (HCH;COO)
15 . Find the mass in 2.6 mol of CxH,z (which is called windowpane). Updating … - Most searched keywords: Whether you are looking for SOLVED:What is the mass in grams of [.56 moles of aspartame?
How many molecules are in 0.005g of aspartame?
How many atoms of nitrogen are in [.2 grams of aspartame?
How many moles in 28 grams of UOz
What is the mass of 5 moles of curious chloride (CmCl;)
13. Find the numbcr of moles of chlorous acid (HCIOz) in 452 g of chlorous acid.
14, Find the grams in [.26 x 10-4 mol of acetic acid (HCH;COO)
15 . Find the mass in 2.6 mol of CxH,z (which is called windowpane). Updating VIDEO ANSWER:sea of discussion. So malls of as part time that is given 1.56 moles and moller mass of S. Part time that we get with the help of product table that is 2 94.3 g per mole. So in this question we use the concept of mall and mass. So a number of moles can be calculated by using this formula mass upon molar mass. So here we have to find the mask because malls and moller mass. We know. So the mask of expert team that is equal to malls multiplied by the molar mass of S. Party. So this mall and mall cancel out. So we get the value of mass of S. Part time which is for 59.1 g. In the the part of this question the mass of S. Part time that is given 0.5 g. And moles of aspartame can be calculated mass upon molar mass. So we get the value of malls of S. Part time which is 1.6 99 into 10 power minus five. Mall and one mole of aspartame contains 6.0 22 into 10 power 23 molecules. So therefore 1.6 99 into 10 power minus five. Mall of aspartame contains. How many molecules so simply multiply Advocate owes number which is this 6.022 into 10 power 23, multiplied by 1.6 99 into 10 power minus five. So we get the value of molecules of S. Part time, 1.02 into 10 power 9, 10 power 19 molecule. So in the next party of this question the mask of s. Part time that is given 1.2 g and moles that is mass upon molar mass. So we get the value 0.408 mol. And one mole of aspartame contained that advocate owes number molecules and 4.408 mol of aspartame contains how many molecules which is 0.2 46 into 10 power 23 molecule. And we know one molecule of aspartame having two atoms of nitrogen. As you can see the formula of uh s part time. So therefore I can see if one molecule of aspartame contained two atoms of nitrogen. Then 4.0 to 46 into 10 power 23 molecule of aspartame contains. How many atoms of nitrogen to simply multiply this term. And we get the value of 4.92 into 10 power 21 atoms of nitrogen in the next in the coast number 11 we have to find out the malls. So the molar mass of this C. Uo 22 negative. So this uranium oxide basically a nine so 2 70 g per mole. So malls can be calculated mass, bone molar masses and masses given. So this crime and graham cancel out. So we get the value of malls Which is equal to 2.10 formal. And in this question number 12 the mask is uh the mass We have to find out. The malls is given five. Mall and moller mass. That is uh this CMC L. Three which is 3 53 g per mole. So moller mass is 3 53 g per mole. So this small and mall cancel out. And on multiplication we get the value of mass which is uh 1767.15 g. In the next question we have to find out the small so again the molar mass of this at cielo two which is 68.46 g per mole. The masses given 4 52. So this crime and graham cancel out. So we get the value of malls which is a 6.60 to 4. And in the next part of this question the next question. So in the next question we have to find out the masks. So moller mass of this acidic acid which is 60 g per mole malls is given to substitute the value. So we get the value of mass uh of this ascetic acid. So the mask of acidic acid that is equal to 75.6 into 10 power minus four g. And in the next question we have to again find out the mask but the molar mass of C eight H 12 which is 108 g per mole. So malls argument. So multiply by moller mass we get the value of mass of the smaller and more cancel out. So we get the value of masks of c eight h 18 that is equal to 2 80.8 graham. So thank you so much for watching this video. - Table of Contents:
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How many molecules are in 0.005g of aspartame?
How many atoms of nitrogen are in [.2 grams of aspartame?
How many moles in 28 grams of UOz
What is the mass of 5 moles of curious chloride (CmCl;)
13. Find the numbcr of moles of chlorous acid (HCIOz) in 452 g of chlorous acid.
14, Find the grams in [.26 x 10-4 mol of acetic acid (HCH;COO)
15 . Find the mass in 2.6 mol of CxH,z (which is called windowpane).
How many molecules of water are present in 5g sample? | MyTutor
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- Most searched keywords: Whether you are looking for How many molecules of water are present in 5g sample? | MyTutor Updating In order to measure the amount of water molecules, we need to use following equation:n = m / M where n is the amount of water molecules in molesm is the mass in g…
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How many molecules are in 5 mg of aspartame class 11 chemistry CBSE
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- Summary of article content: Articles about How many molecules are in 5 mg of aspartame class 11 chemistry CBSE Aspartame is a methyl ester of the phenylalanine dipepte of aspartic ac. In the place of sugar, the aspartame can be used for reducing the calories. …
- Most searched keywords: Whether you are looking for How many molecules are in 5 mg of aspartame class 11 chemistry CBSE Aspartame is a methyl ester of the phenylalanine dipepte of aspartic ac. In the place of sugar, the aspartame can be used for reducing the calories. How many molecules are in 5 mg of aspartame
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how many molecules are in 5 mg of aspartame? – Brainly.ph
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how many molecules are in 5.0 mg of aspartame
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- Summary of article content: Articles about how many molecules are in 5.0 mg of aspartame C. Calculate the mass in grams of 1.56 mol aspartame? (mol asp = 10.0 gasp x asp. = 5.0. E. 1.56 past asp x d. How many molecules are in 5.0 mg aspartame? …
- Most searched keywords: Whether you are looking for how many molecules are in 5.0 mg of aspartame C. Calculate the mass in grams of 1.56 mol aspartame? (mol asp = 10.0 gasp x asp. = 5.0. E. 1.56 past asp x d. How many molecules are in 5.0 mg aspartame?
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OneClass: How many molecules are in 5 mg of aspartame?
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how many molecules are in 5.0 mg of aspartame
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Answered: The molecular formula of aspartame is… | bartleby
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- Summary of article content: Articles about Answered: The molecular formula of aspartame is… | bartleby This is the answer 3.4 x 10^-2 moles c) What is the mass in grams of 1.56 moles of aspartame? This is the answer 458.64 grams d) How many molecules are in 5 mg … …
- Most searched keywords: Whether you are looking for Answered: The molecular formula of aspartame is… | bartleby This is the answer 3.4 x 10^-2 moles c) What is the mass in grams of 1.56 moles of aspartame? This is the answer 458.64 grams d) How many molecules are in 5 mg … Solution for The molecular formula of aspartame is C14H18N205. a) Calculate the gram-formula-mass of aspartame. This is the answer 294 g/mol b) How many moles…
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How many hydrogen atoms are present in 5.00 mg of aspartame? – Answers
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- Summary of article content: Articles about How many hydrogen atoms are present in 5.00 mg of aspartame? – Answers The chemical formula for Aspartame is C14H18N2O5. The molar weight is 294.3 grams/mol, so there are .00001699 moles of aspartame. …
- Most searched keywords: Whether you are looking for How many hydrogen atoms are present in 5.00 mg of aspartame? – Answers The chemical formula for Aspartame is C14H18N2O5. The molar weight is 294.3 grams/mol, so there are .00001699 moles of aspartame. The chemical formula for Aspartame is C14H18N2O5. The molar
weight is 294.3 grams/mol, so there are .00001699 moles of
aspartame. Using Avogadro’s number, there are 1.023 E19 molecules,
each containing 18 hydrogen atoms. So there are 1.842 E20 atoms of
hydrogen. - Table of Contents:
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Percent Composition By Mass – how many molecules are in 5 mg of aspartame
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How many molecules are in 5 mg of aspartame?
We’re asked to find the number of molecules of a given mass of a substance. We can do this using the molar mass of the substance and Avogadro’s constant, #6.022 xx 10^23# .
Aspartame has the chemical formula #”C”_14″H”_18″N”_2″O”_5# , and its molar mass is calculated to be #294.30# #”g/mol”# .
Let’s convert the given mass ( #5# #”mg”# ) to moles of aspartame:
#5cancel(“mg”)((1cancel(“g”))/(10^3cancel(“mg”)))((1color(white)(l)”mol”)/(294.30cancel(“g”))) = color(red)(1.70 xx 10^-5# #color(red)(“mol aspartame”#
Using Avogadro’s constant, we can convert this value to molecules as so:
#color(red)(1.70xx10^-5)cancel(color(red)(“mol”))((6.022xx10^23color(white)(l)”molecules”)/(1cancel(“mol”)))#
#= color(blue)(1 xx 10^19# #color(blue)(“molecules aspartame”#
which I’ll leave at one significant figure, as allowed by the problem..
SOLVED:What is the mass in grams of [.56 moles of aspartame? How many molecules are in 0.005g of aspartame? How many atoms of nitrogen are in [.2 grams of aspartame? How many moles in 28 grams of UOz
Video Transcript
sea of discussion. So malls of as part time that is given 1.56 moles and moller mass of S. Part time that we get with the help of product table that is 2 94.3 g per mole. So in this question we use the concept of mall and mass. So a number of moles can be calculated by using this formula mass upon molar mass. So here we have to find the mask because malls and moller mass. We know. So the mask of expert team that is equal to malls multiplied by the molar mass of S. Party. So this mall and mall cancel out. So we get the value of mass of S. Part time which is for 59.1 g. In the the part of this question the mass of S. Part time that is given 0.5 g. And moles of aspartame can be calculated mass upon molar mass. So we get the value of malls of S. Part time which is 1.6 99 into 10 power minus five. Mall and one mole of aspartame contains 6.0 22 into 10 power 23 molecules. So therefore 1.6 99 into 10 power minus five. Mall of aspartame contains. How many molecules so simply multiply Advocate owes number which is this 6.022 into 10 power 23, multiplied by 1.6 99 into 10 power minus five. So we get the value of molecules of S. Part time, 1.02 into 10 power 9, 10 power 19 molecule. So in the next party of this question the mask of s. Part time that is given 1.2 g and moles that is mass upon molar mass. So we get the value 0.408 mol. And one mole of aspartame contained that advocate owes number molecules and 4.408 mol of aspartame contains how many molecules which is 0.2 46 into 10 power 23 molecule. And we know one molecule of aspartame having two atoms of nitrogen. As you can see the formula of uh s part time. So therefore I can see if one molecule of aspartame contained two atoms of nitrogen. Then 4.0 to 46 into 10 power 23 molecule of aspartame contains. How many atoms of nitrogen to simply multiply this term. And we get the value of 4.92 into 10 power 21 atoms of nitrogen in the next in the coast number 11 we have to find out the malls. So the molar mass of this C. Uo 22 negative. So this uranium oxide basically a nine so 2 70 g per mole. So malls can be calculated mass, bone molar masses and masses given. So this crime and graham cancel out. So we get the value of malls Which is equal to 2.10 formal. And in this question number 12 the mask is uh the mass We have to find out. The malls is given five. Mall and moller mass. That is uh this CMC L. Three which is 3 53 g per mole. So moller mass is 3 53 g per mole. So this small and mall cancel out. And on multiplication we get the value of mass which is uh 1767.15 g. In the next question we have to find out the small so again the molar mass of this at cielo two which is 68.46 g per mole. The masses given 4 52. So this crime and graham cancel out. So we get the value of malls which is a 6.60 to 4. And in the next part of this question the next question. So in the next question we have to find out the masks. So moller mass of this acidic acid which is 60 g per mole malls is given to substitute the value. So we get the value of mass uh of this ascetic acid. So the mask of acidic acid that is equal to 75.6 into 10 power minus four g. And in the next question we have to again find out the mask but the molar mass of C eight H 12 which is 108 g per mole. So malls argument. So multiply by moller mass we get the value of mass of the smaller and more cancel out. So we get the value of masks of c eight h 18 that is equal to 2 80.8 graham. So thank you so much for watching this video.
How many molecules are in 5 mg of aspartame class 11 chemistry CBSE
Hint: Aspartame is an artificial sweetener which is a non-saccharide sweetener. This is having \[200\] times sweeter than sucrose. The aspartame is substituted over sugar in foods and beverages. Aspartame is a methyl ester of the phenylalanine dipeptide of aspartic acid. In the place of sugar, the aspartame can be used for reducing the calories. Aspartame is having the formula of \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] .
Complete step by step solution:
The \[1\,g\] of molecules will be equal to \[1\] mole.
In equation;
\[1\,g\]of molecule \[ = \,\,1\,\]mole
Since, \[1\] mole contains Avogadro’s number (\[{N_A}\] ) of molecule
So, \[1\,mole\, = \,6.022\, \times \,{10^{23}}\,molecule\]
Therefore, for \[1\] molecule will be;
\[1\,\,molecule\, = \,\dfrac{1}{{6.022\, \times \,{{10}^{23}}}}\,g\,\,molecule\]
So, the answer will be;
\[1\,molecule\, = 1.66\, \times \,{10^{ – 24}}\,g\,molecule\]
\[1\] mole Aspartame contains Avogadro’s number (\[{N_A}\] ) of molecule.
Number of moles is calculated by using below given formula;
\[n\,\, = \,\,\dfrac{{mass}}{{molar\,mass}}\]
where \[n\] is the amount in moles \[(mol)\] , mass in grams \[\;(g)\] , and molar mass in grams per mole \[\;(g/mol)\] .
The given values are;
Mass of aspartame= \[5{\text{ }}mg\]
Molar mass of aspartame; \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
There are \[14\] Carbon atoms and carbon molar mass is \[\left( {12.0{\text{ }}g/mol} \right)\] ,
\[18\] Hydrogens atoms and hydrogen’s molar mass is \[\left( {1.008{\text{ }}g/mol} \right)\]
\[2\] Nitrogen atoms and nitrogen’s molar mass is \[\left( {{\text{14}}{\text{.0 }}g/mol} \right)\]
and \[5\] Oxygen atom and the oxygen’s molar mass is \[\left( {16.0{\text{ }}g/mol} \right){\text{ }}\]
Molar mass of \[{C_{14}}{H_{18}}{N_2}{O_5}\,\] ;
\[\left( {14 \times 12.0{\text{ }}g/mol{\text{ }}C} \right){\text{ }} + {\text{ }}\left( {18 \times 1.00{\text{ }}g/mol{\text{ }}H} \right){\text{ }} + {\text{ }}\left( {2 \times 14.0{\text{ }}g/mol{\text{ N}}} \right){\text{ }} + {\text{ }}\left( {5 \times 16.0{\text{ }}g/mol{\text{ }}O} \right){\text{ }}\] \[ = {\text{ 214 }}g/mol{\text{ }}{C_{14}}{H_{18}}{N_2}{O_5}\,\]
\[n\,\, = \,\,\dfrac{{5\,mg}}{{214\,g/mol}}\]
Since,
\[1\,g = \,{10^3}\,mg\]
Therefore,
\[ = \,\dfrac{{5\, \times \,{{10}^3}\,g}}{{214\,g/mol}}\]
\[ = 1.70\, \times \,{10^{ – 5}}\,mol\]
So, the number of moles \[ = 1.70\, \times \,{10^{ – 5}}\,mol\]
Using the Avogadro’s constant, we need to convert the values into molecules;
\[1.70 \times {10^{ – 5}}\,\,mol\, \times \,\dfrac{{6.022\, \times \,{{10}^{23}}\,\,molecules}}{{1\,mol}}\,\]
\[ = \,\,1\, \times \,{10^{19}}\,\,molecules\] of aspartame.
Note: A mole is a unit measurement for the amount of substance in an international system of units i.e., SI unit. A mole of a particle or a mole of a substance is defined as \[6.02214076 \times {10^{23}}\] of a chemical unit, that can be ions, atoms, molecules, etc. Originally it was defined as the number of atoms in \[12{\text{ }}g\] of carbon-12.
So you have finished reading the how many molecules are in 5.0 mg of aspartame topic article, if you find this article useful, please share it. Thank you very much. See more: how many atoms of nitrogen are in 1.2 grams of aspartame, how many atoms of nitrogen are in 1 mole of aspartame, how many hydrogen atoms are present in 2.00 mg of aspartame?, how many hydrogen atoms are present in 3.50 mg of aspartame?, how many hydrogen atoms are present in 5.00 mg of aspartame?, how many moles of aspartame are present in 3.50 mg of aspartame?, how many molecules are in 100g of aspartame, how many hydrogen atoms are present in 2.50 mg of aspartame?
