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How much heat transfer in kilocalories is required to thaw a 0.450 kg package of frozen vegetables originally at 0º if their heat of fusion is the same as that of water?
And then, we multiply that by the mass of 0.45 kilograms. And, this means the amount of heat required will be 35.9 kilocalories to melt the vegetables.
How can you increase the rate of heat transfer?
- Changing fluid flow. Increase the flow rate. Jet impingement. Additive insertion. …
- Physical properties of alternating fluids.
- Change the heat exchange surface condition. Increase wall roughness. Change the shape and size of heat exchange surface.
How does heat capacity affect temperature change?
The heat capacity tells us how much energy is needed to change the temperature of a given substance assuming that no phase changes are occurring.
How do you calculate change in temperature?
This is easy. You subtract the final temperature from the starting temperature to find the difference. So if something starts at 50 degrees Celsius and finishes at 75 degrees C, then the change in temperature is 75 degrees C – 50 degrees C = 25 degrees C. For decreases in temperature, the result is negative.
Which condition is necessary for heat transfer to occur two objects that are in contact must have?
What is needed for heat transfer to take place is a difference in temperature between two objects. Without this difference, no heat transfer can take place. Heat can be transferred in three ways: by conduction, by convection, and by radiation.
What conditions are necessary for heat conduction?
(i) The two objects should be in direct contact with each other. (ii) The temperature of the two objects should be different. Heat will flow only from a hotter object to a cooler object.
What conditions are necessary for heat conduction to occur between two objects?
What conditions are necessary for heat conduction to occur between two objects? The objects must be surrounded by air or water. Two objects at different temperatures are touching one another.
What keeps the water at the top of the beaker the same temperature as that of the bottom?
What keeps the water at the top of the beaker the same temperature as that of the bottom? Heat from the burner radiates through the liquid and causes even heating. Heated water molecules and steam rise in the beaker, carrying heat by convection.
OpenStax College Physics Solution, Chapter 14, Problem 11 (Problems & Exercises) | OpenStax College Physics Answers
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- Summary of article content: Articles about brainly.com What is being thawed here actually is the frozen ice into liqu water which is in the vegetables. From the references, the latent heat of fusion of water is: Δ … …
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OpenStax College Physics Solution, Chapter 14, Problem 11 (Problems & Exercises) | OpenStax College Physics Answers
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14.17 | How much heat transfer is necessary to raise the temperature of a 0.200-kg piece of ice from – YouTube
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How much heat transfer (in kilocalories) is required to thaw a 0.598 kg package of frozen vegetables originally at 0 degree C if their heat of fusion is the same as that of water? | Study.com
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OpenStax College Physics Solution, Chapter 14, Problem 11 (Problems & Exercises)
Video Transcript
This is College Physics Answers with Shaun Dychko. To change the state of frozen vegetables into water at a constant temperature, the amount of heat required will be just the latent heat of fusion. Fusion is maybe not the right word here because we’re melting it, not fusing it, but it’s the same thing whether you’re making it solid or making it liquid. It’s the same factor to use. So, the latent heat of fusion for water is 79.8 kilocalories per kilogram per Celsius degree. And then, we multiply that by the mass of 0.45 kilograms. And, this means the amount of heat required will be 35.9 kilocalories to melt the vegetables.
OpenStax College Physics Solution, Chapter 14, Problem 11 (Problems & Exercises)
Video Transcript
This is College Physics Answers with Shaun Dychko. To change the state of frozen vegetables into water at a constant temperature, the amount of heat required will be just the latent heat of fusion. Fusion is maybe not the right word here because we’re melting it, not fusing it, but it’s the same thing whether you’re making it solid or making it liquid. It’s the same factor to use. So, the latent heat of fusion for water is 79.8 kilocalories per kilogram per Celsius degree. And then, we multiply that by the mass of 0.45 kilograms. And, this means the amount of heat required will be 35.9 kilocalories to melt the vegetables.
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