Top 6 Oracle Mod 5457 Votes This Answer

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Oracle MOD Function

Oracle / PLSQL: MOD Function

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Summary of article content: Articles about Oracle / PLSQL: MOD Function The Oracle/PLSQL MOD function returns the remainder of m dived by n. Syntax. The syntax for the MOD function in Oracle/PLSQL is: MOD( m, n ). Parameters or … …
Most searched keywords: Whether you are looking for Oracle / PLSQL: MOD Function The Oracle/PLSQL MOD function returns the remainder of m dived by n. Syntax. The syntax for the MOD function in Oracle/PLSQL is: MOD( m, n ). Parameters or … This Oracle tutorial explains how to use the Oracle / PLSQL MOD function with syntax and examples. The Oracle / PLSQL MOD function returns the remainder of m divided by n.techonthenet, tech on the net, totn, oracle, plsql, functions, mod function, syntax, parameters, arguments, example, tutorial
Table of Contents:

Description

Syntax

Calculation

Returns

Note

Applies To

Example

Oracle / PLSQL: MOD Function

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Summary of article content: Articles about Oracle MOD() function – w3resource The Oracle MOD() is used to return the remainder of a divend dived by a divisor. This function also works on fractional values and … …
Most searched keywords: Whether you are looking for Oracle MOD() function – w3resource The Oracle MOD() is used to return the remainder of a divend dived by a divisor. This function also works on fractional values and … Oracle MOD() math function, MySql Tutorial, w3resourceOracle MOD() returns the remainder of a number divided by another number.
Table of Contents:

Oracle MOD() function - w3resource — Oracle MOD() function – w3resource

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Summary of article content: Articles about Oracle REMAINDER and MOD Function Guide, FAQ, and Examples – Database Star The Oracle MOD function performs a “modulo division”, which means that it gets the remainder of one number dived by another number. It returns the leftover of … …
Most searched keywords: Whether you are looking for Oracle REMAINDER and MOD Function Guide, FAQ, and Examples – Database Star The Oracle MOD function performs a “modulo division”, which means that it gets the remainder of one number dived by another number. It returns the leftover of … The Oracle MOD and REMAINDER functions are very similar and are useful for working with numbers. Learn what they are, and the differences, in this article.
Table of Contents:

Purpose of the Oracle REMAINDER and MOD Functions

What’s the Difference between Oracle MOD and REMAINDER

Oracle REMAINDER Syntax and Parameters

Oracle MOD Syntax

Is There A Oracle MOD DIV Function

How Can You Select Every Second Row Using Oracle MOD and Rownum

Can You Use Oracle MOD Function In a WHERE Clause

Examples of the REMAINDER Function

Oracle MOD() function

Oracle MOD() function

Last update on May 30 2022 11:02:49 (UTC/GMT +8 hours)

Description

The Oracle MOD() is used to return the remainder of a dividend divided by a divisor. This function also works on fractional values and returns the exact remainder. The function returns dividend when the value of divisor is 0.

The function takes any numeric or nonnumeric data type (can be implicitly converted to a numeric data type) as an argument.

If the argument is BINARY_FLOAT, then the function returns BINARY_DOUBLE. Otherwise, the function returns the same numeric data type as the argument

Syntax:

MOD(N,M)

Arguments:

Name Description N Dividend. M Divisor.

Pictorial Presentation of MOD() function

Example-1:

The statement below returns the remainder of17 divided by 2.

SELECT MOD(7,2) FROM dual;

Here is the result.

MOD(7,2) ———- 1

Example-2:

The statement below returns the remainder of 7 divided by -2.

SELECT MOD(7,-2) FROM dual;

Here is the result.

MOD(7,-2) ———- 1

Example-3:

The statement below returns the remainder of -7 divided by 2.

SELECT MOD(-7, 2);

Here is the result.

MOD(-7,2) ———- -1

Example-4:

The statement below returns the remainder of -7 divided by -2.

SELECT MOD(-7, -2);

Here is the result.

MOD(-7,-2) ———- -1

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MOD() Function in Oracle

In Oracle, the MOD() function returns the modulo operation. In other words, it returns the remainder of its first argument divided by its second.

Syntax

The syntax goes like this:

MOD(n2, n1)

Each argument can be any numeric data type or any nonnumeric data type that can be implicitly converted to a numeric data type.

Example

Here’s an example:

SELECT MOD(100, 6) FROM DUAL;

Result:

MOD(100,6) _____________ 4

Oracle MOD() vs Classical Modulus

Oracle’s MOD() function behaves differently from the classical mathematical modulus function, if the product of n1 and n2 is negative.

Here’s an example that demonstrates how each of these differ:

SELECT MOD(100, 6) AS “Oracle MOD()”, 100 – 6 * FLOOR(100/6) AS “Classical” FROM DUAL UNION ALL SELECT MOD(100, -6), 100 – -6 * FLOOR(100/-6) FROM DUAL UNION ALL SELECT MOD(-100, 6), -100 – 6 * FLOOR(-100/6) FROM DUAL UNION ALL SELECT MOD(-100, -6), -100 – -6 * FLOOR(-100/-6) FROM DUAL;

Result:

Oracle MOD() Classical ____________ _________ 4 4 4 -2 -4 2 -4 -4

Non-Numeric Arguments

The arguments can be any numeric data type or any nonnumeric data type that can be implicitly converted to a numeric data type.

Here’s an example of what happens when the arguments don’t satisfy that criteria:

SELECT MOD(‘Homer’, ‘Symptom’) FROM DUAL;

Result:

Error starting at line : 1 in command – SELECT MOD(‘Homer’, ‘Symptom’) FROM DUAL Error report – ORA-01722: invalid number

Null Arguments

MOD() returns null if any argument is null :

SET NULL ‘null’; SELECT MOD(null, 16), MOD(1024, null), MOD(null, null) FROM DUAL;

Result:

MOD(NULL,16) MOD(1024,NULL) MOD(NULL,NULL) _______________ _________________ _________________ null null null

By default, SQLcl and SQL*Plus return a blank space whenever a null value occurs as a result of a SQL SELECT statement.

However, you can use SET NULL to specify a different string to be returned. Here I specified that the string null should be returned.

Missing Arguments

Calling MOD() with the wrong number of arguments, or without any arguments results in an error:

SELECT MOD() FROM DUAL;

Result:

Error starting at line : 1 in command – SELECT MOD() FROM DUAL Error at Command Line : 1 Column : 8 Error report – SQL Error: ORA-00909: invalid number of arguments 00909. 00000 – “invalid number of arguments” *Cause: *Action:

And:

SELECT MOD(10, 2, 3) FROM DUAL;

Result:

Error starting at line : 1 in command – SELECT MOD(10, 2, 3) FROM DUAL Error at Command Line : 1 Column : 8 Error report – SQL Error: ORA-00909: invalid number of arguments 00909. 00000 – “invalid number of arguments” *Cause: *Action:

Modulo Functions

Advanced Oracle SQL: Modulo Functions Oracle Tips by Laurent Schneider

Laurent Schneider is considered one of the top Oracle SQL experts, and he is the author of the book “Advanced SQL Programming” by Rampant TechPress. The following is an excerpt from the book.

SELECT

X.COLUMN_VALUE X,

Y.COLUMN_VALUE Y,

MOD(X.COLUMN_VALUE, Y.COLUMN_VALUE) “MOD(X,Y)”,

REMAINDER(X.COLUMN_VALUE, Y.COLUMN_VALUE) “REMAINDER(X,Y)”

FROM

TABLE(SYS.ODCINUMBERLIST(-30,-20,20,30)) X,

TABLE(SYS.ODCINUMBERLIST(-7,7)) Y;

X Y MOD(X,Y) REMAINDER(X,Y)

———- ———- ———- ————–

-30 -7 -2 -2

-30 7 -2 -2

-20 -7 -6 1

-20 7 -6 1

20 -7 6 -1

20 7 6 -1

30 -7 2 2

30 7 2 2

MOD and REMAINDER return the rest of the integer division. Here 30/7=4 remains 2. MOD truncates the quotient and REMAINDER rounds it. 20/7 is equal to 2.857. For MOD, 20/7=2 remains 6. For REMAINDER, 20/7=3 remains -1. For negative numbers, the sign of the first argument determines the sign of the modulo and the remainder.

SELECT

MOD(5, 0)

FROM

DUAL;

MOD(5,0)

———-

5

Another special case is modulo 0. In Perl or in C, modulo 0 is illegal. REMAINDER returns an error for modulo 0 but MOD returns the first argument.

Functions to search and modify strings

SELECT

ENAME,

SUBSTR(ENAME, 1, 2)

FROM

EMP;

ENAME SU

———- —

SMITH SM

ALLEN AL

WARD WA

JONES JO

MARTIN MA

BLAKE BL

CLARK CL

SCOTT SC

KING KI

TURNER TU

ADAMS AD

JAMES JA

FORD FO

MILLER MI

SUBSTR returns a substring of the employee name, starting at position 1. The third parameter is the maximum length; by default, the rest of the string is returned.

SELECT

INSTR

(

‘Programming’,

‘ra’,

1,

2

) RA

FROM

DUAL;

RA

———-

25

INSTR returns the position of the second match of the string ‘ra’, starting at position 1.

SUBSTR and INSTR are often used together:

SELECT

SUBSTR

(

COLUMN_VALUE,

INSTR

(

COLUMN_VALUE,

‘ ‘

)+1,

INSTR

(

COLUMN_VALUE,

‘ ‘,

1,

2

)-

INSTR

(

COLUMN_VALUE,

‘ ‘

)-1

) “WORD2”

FROM

TABLE(SYS.ODCIVARCHAR2LIST(‘Programming’));

WORD2

———-

Oracle

The second word is the substring starting right after the first space and for a length equal to the difference between the position of the first space and the position of the second space.

LENGTH returns the length of a string. LPAD and RPAD are left and right padding functions.

SELECT

LPAD(DNAME, 20, ‘.’) LEFT,

RPAD(DNAME, 20, ‘.’) RIGHT,

RPAD(LPAD(DNAME, 10+LENGTH(DNAME)/2, ‘.’), 20, ‘.’) MIDDLE

FROM

DEPT;

LEFT RIGHT MIDDLE

——————– ——————– ——————–

……….ACCOUNTING ACCOUNTING………. …..ACCOUNTING…..

…………RESEARCH RESEARCH………… ……RESEARCH……

……………SALES SALES…………… …….SALES……..

……….OPERATIONS OPERATIONS………. …..OPERATIONS…..

By default, the padding character is a space. LPAD adds the character to the left and RPAD to the right. To get the center effect, the string is first padded to 10 + half of the length of the string, then padded to 20.

To remove characters from the left and from the right, three functions are available – TRIM, LTRIM and RTRIM. By default, TRIM removes trailing and leading spaces.

SELECT

ENAME,

TRIM(LEADING ‘S’ FROM ENAME),

TRIM(TRAILING ‘S’ FROM ENAME),

TRIM(BOTH ‘S’ FROM ENAME)

FROM

EMP

WHERE

ENAME LIKE ‘%S%’;

ENAME TRIM(LEADI TRIM(TRAIL TRIM(BOTH’

———- ———- ———- ———-

SMITH MITH SMITH MITH

JONES JONES JONE JONE

SCOTT COTT SCOTT COTT

ADAMS ADAMS ADAM ADAM

JAMES JAMES JAME JAME

TRIM removes either spaces, by default, or any other single character from the string by taking them from either the left, the right or from both sides (default). The leading and trailing Ss are removed from the employee names:

SELECT

ENAME,

LTRIM(ENAME, ‘BCDFGHJKLMNPQRSTVWXZ’),

RTRIM(ENAME, ‘BCDFGHJKLMNPQRSTVWXZ’)

FROM

EMP

WHERE

ROWNUM<6; ENAME LTRIM(ENAM RTRIM(ENAM ---------- ---------- ---------- SMITH ITH SMI ALLEN ALLEN ALLE WARD ARD WA JONES ONES JONE MARTIN ARTIN MARTI LTRIM and RTRIM remove either spaces, by default, or any other character from a character string from the left or from the right. The consonants left and right to the name are trimmed. Note that TRIM does not support the removal of more than one character while LTRIM and RTRIM support removing character from a list of character, i.e. a string: SELECT * FROM TABLE(SYS.ODCIVARCHAR2LIST('123','ABC456','789GHI','JKL')) WHERE LTRIM(COLUMN_VALUE,'0123456789') IS NULL; COL --- 123 Note: For VARCHAR2 and CHAR, an empty string is null and has a length of NULL. For CLOB, the empty string is not null and has a length of 0. The LTRIM functions returns an empty string where the string contains only digits. TRANSLATE substitutes one character for another character and REPLACE substitutes a string for another string: SELECT LOC, REPLACE(LOC,'YORK','ORLEANS'), TRANSLATE(LOC,'AOIEY ','@013') FROM DEPT; LOC REPLACE(LOC,'YO TRANSLATE(LOC ------------- --------------- ------------- NEW YORK NEW ORLEANS N3W0RK DALLAS DALLAS D@LL@S CHICAGO CHICAGO CH1C@G0 BOSTON BOSTON B0ST0N The string 'YORK' is searched and replaced by the string 'ORLEANS'. When the last argument is omitted, the searched string is deleted from the original string. TRANSLATE substitutes each 'A', 'O', 'E', 'I', 'Y' and ' ' with '@', '0', '3', '1', NULL and NULL, respectively. When the third argument is shorter than the second, the characters from the first string that have no correspondence are removed. The third argument is not optional and if it is NULL, TRANSLATE returns NULL. UPPER, LOWER and INITCAP change the case of the string: SELECT UPPER(COLUMN_VALUE), LOWER(COLUMN_VALUE), INITCAP(COLUMN_VALUE) FROM TABLE(SYS.ODCIVARCHAR2LIST('JoHn sMiTh')); UPPER(COLU LOWER(COLU INITCAP(CO ---------- ---------- ---------- JOHN SMITH john smith John Smith UPPER returns everything in uppercase, LOWER in lowercase and INITCAP capitalizes the first letter of each word and sets the other letters to lowercase.

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Top 6 Oracle Mod 5457 Votes This Answer

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