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How to make ORDER SIBLINGS BY – SQL

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ORDER SIBLINGS BY Clause

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Summary of article content: Articles about ORDER SIBLINGS BY Clause The ORDER SIBLINGS BY clause is val only in a hierarchical query. The optional SIBLINGS keyword specifies an order that first sorts the parent rows, … …
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ORDER SIBLINGS BY Clause

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Summary of article content: Articles about sql – How to make ORDER SIBLINGS BY? – Stack Overflow This would achieve what you describe: For one level of hierarchy. WITH RECURSIVE t AS ( SELECT emp_ As top_ , emp_ , manager_ … …
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Summary of article content: Articles about How to order SIBLINGS in Oracle hierarchy queries | TechRepublic Developers can use the ORDER SIBLINGS BY feature of Oracle 10g and later to sort the records in a hierarchy created by the START WITH and … …
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How to order SIBLINGS in Oracle hierarchy queries | TechRepublic

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ORDER SIBLINGS BY Clause

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Summary of article content: Articles about SQL Server Tương đương với Oracle ‘CONNECT BY PRIOR’ và ‘ORDER SIBLINGS BY’ Mô phỏng order siblings by phức tạp hơn một chút. Giả sử chúng ta có một cột sort_order xác định thứ tự của các phần tử trên mỗi phụ huynh (không phải thứ tự … …
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ORDER SIBLINGS BY Clause

The ORDER SIBLINGS BY clause is valid only in a hierarchical query. The optional SIBLINGS keyword specifies an order that first sorts the parent rows, and then sorts the child rows of each parent for every level within the hierarchy.

Rows that have duplicate lists of values in the columns specified after the SIBLINGS BY keywords are arbitrarily ordered among the rows with the same list of values and the same parent. If a hierarchical query includes the ORDER BY clause without the SIBLINGS keyword, rows are ordered according to the sort specifications that follow the ORDER BY keywords. Neither the ORDER BY clause nor the ORDER SIBLINGS BY option to the ORDER BY clause is required in hierarchical queries.

The hierarchical query in the following example returns the subset of rows in the hierarchical data set whose root is Goyal, as listed in the topic Hierarchical Clause. This query includes the ORDER SIBLINGS BY clause to sort by name the employees who report to the same manager: SELECT empid, name, mgrid, LEVEL FROM employee START WITH name = ‘Goyal’ CONNECT BY PRIOR empid = mgrid ORDER SIBLINGS BY name; The rows returned by this query are sorted in the following order: empid name mgrid level 16 Goyal 17 1 12 Henry 16 2 7 O’Neil 12 3 9 Shoeman 12 3 8 Smith 12 3 14 Scott 16 2 11 Zander 16 2 6 Barnes 11 3 5 McKeough 11 3 9 row(s) retrieved. Goyal row at the root of this hierarchy. Two subsequent CONNECT BY steps (marked as 2 and 3 in the level pseudocolumn) returned three sets of sibling rows: Henry , Scott , and Zander are siblings whose parent is Goyal ;

, , and are siblings whose parent is ; O’Neil , Shoeman , and Smith are siblings whose parent is Henry ;

, , and are siblings whose parent is ; Barnes and McKeough are siblings whose parent is Zander. The next CONNECT BY step returned no rows, because the rows for which level = 3 are leaf nodes within this hierarchy. At this point in the execution of the query, the ORDER SIBLINGS BY clause was applied to the result set, sorting the rows in the order shown above. Here the START WITH clause returned therow at the root of this hierarchy. Two subsequent CONNECT BY steps (marked asandin thepseudocolumn) returned three sets of sibling rows:The next CONNECT BY step returned no rows, because the rows for whichare leaf nodes within this hierarchy. At this point in the execution of the query, the ORDER SIBLINGS BY clause was applied to the result set, sorting the rows in the order shown above. Because the sort key, name, is a VARCHAR column, the returned rows within each set of siblings are in the ASCII order of their employee.name values. Only the sets of siblings that are leaf nodes in the hierarchy of returned rows appear consecutively in the sorted result set, because the managers are immediately followed by the employees who report to them, rather than by their siblings. An exception in this example is Scott, whose child nodes form an empty set.

How to make ORDER SIBLINGS BY?

I’m using PostgreSQL 9.1.6 and trying to build recursive SQL.

I want to sort like ORDER SIBLINGS BY in SQL-Server does it.

Editor’s note: This is probably supposed to refer to Oracle, where ORDER SIBLINGS BY actually exists.

Test table:

create table RECURSIVE_TEST( EMP_ID int, MANAGER_ID int, EMP_NAME varchar(30) ); insert into recursive_test values (1 ,0 ,’MANAGER1′), (2 ,0 ,’MANAGER2′), (3 ,0 ,’MANAGER3′), (4 ,0 ,’MANAGER4′), (5 ,1 ,’emp1′), (6 ,3 ,’emp2′), (7 ,4 ,’emp3′), (8 ,2 ,’emp4′), (9 ,2 ,’emp5′), (10 ,3 ,’emp6′), (11 ,4 ,’emp7′), (12 ,3 ,’emp8′), (13 ,4 ,’emp9′), (14 ,2 ,’emp10′), (15 ,2 ,’emp11′), (16 ,1 ,’emp12′);

Query:

WITH RECURSIVE T AS ( SELECT A.EMP_ID ,A.MANAGER_ID ,A.EMP_NAME FROM RECURSIVE_TEST A WHERE MANAGER_ID = 0 UNION ALL SELECT A.EMP_ID ,A.MANAGER_ID ,A.EMP_NAME FROM RECURSIVE_TEST A, T WHERE A.MANAGER_ID = T.EMP_ID ) SELECT * FROM T;

Result:

emp_id | manager_id | emp_name ——–+————+———- 1 | 0 | MANAGER1 2 | 0 | MANAGER2 3 | 0 | MANAGER3 4 | 0 | MANAGER4 5 | 1 | emp1 6 | 3 | emp2 7 | 4 | emp3 8 | 2 | emp4 9 | 2 | emp5 10 | 3 | emp6 11 | 4 | emp7 12 | 3 | emp8 13 | 4 | emp9 14 | 2 | emp10 15 | 2 | emp11 16 | 1 | emp12

I want to sort the result-set up there like below.

emp_id | manager_id | emp_name ——–+————+———- 1 | 0 | MANAGER1 5 | 1 | emp1 16 | 1 | emp12 2 | 0 | MANAGER2 8 | 2 | emp4 9 | 2 | emp5 14 | 2 | emp10 15 | 2 | emp11 3 | 0 | MANAGER3 6 | 3 | emp2 10 | 3 | emp6 12 | 3 | emp8 4 | 0 | MANAGER4 7 | 4 | emp3 11 | 4 | emp7 13 | 4 | emp9

Any advice?

How to order SIBLINGS in Oracle hierarchy queries

Developers can use the ORDER SIBLINGS BY feature of Oracle 10g and later to sort the records in a hierarchy created by the START WITH and CONNECT BY clauses in a SELECT statement.

Oracle’s START WITH and CONNECT BY clauses in the SELECT

statement automatically traverse a hierarchy. Without this feature, a complex

self-join would be required to identify which rows are logically related to

others. The START WITH clause identifies the row or rows to be considered the

starting points, or “roots,” of the hierarchy. The CONNECT BY PRIOR

clause then indicates how to identify which rows are related to each other.

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For example, the query in

Listing A produces a “Reports To” listing from the EMPLOYEES

table in the HR sample schema provided by Oracle.

The LEVEL pseudocolumn indicates

how deeply the report is currently nested; here, I use it to LPAD the employee

names to indent them. The START WITH condition states that only employees 101

and 102 are to be considered as starting points. The CONNECT BY PRIOR clause

then links the employee_id column in one row to the manager_id column in the next, to indicate who reports to

whom.

If you run this query in the HR schema, you’ll notice that

the last names are not sorted within the listing for a specific manager; they

are listed in the order Oracle encountered them in processing the hierarchy.

If you want the subordinates in alphabetical order, you

might try to ORDER BY the original last_name column.

However, this would break up the hierarchy, and turn it back into a flat list

of names.

You might also try to ORDER BY the pseudocolumn

LEVEL first, which tells how deep a specific row is in the hierarchy. This,

too, breaks up the hierarchy—all the managers will be listed first, followed by

people who report to any of them.

In Oracle 10g (both releases), it’s now easy to do this: You

can use the new SIBLINGS keyword to create the correct ordering. The syntax is:

ORDER SIBLINGS BY

So adding the clause:

ORDER SIBLINGS BY last_name

to the end of the query will

preserve the hierarchy and also alphabetize the last names within each level.

Note that the original last_name was used not the

alias “Reports To.” The extra space padding in “Reports To”

would affect the sort, so the original must be used.

Listing B shows the output, both before and after adding ORDER

SIBLINGS BY.

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Bob Watkins (OCP, MCDBA, MCSE, MCT) is a computer professional with 25 years of experience as a technical trainer, consultant, and database administrator. Visit Bob’s site.

So you have finished reading the order siblings by topic article, if you find this article useful, please share it. Thank you very much. See more: ORDER SIBLINGS BY Oracle, ORDER SIBLINGS BY PostgreSQL, Order by in CONNECT BY prior, postgresql connectby example, CONNECT BY trong Oracle, START WITH Oracle, CONNECT BY level trong Oracle, CONNECT BY PRIOR trong Oracle

Top 40 Order Siblings By Quick Answer

ORDER SIBLINGS BY Clause

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ORDER SIBLINGS BY Clause

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How to order SIBLINGS in Oracle hierarchy queries

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