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Can you print in a void method?
void methods can do everything a normal method can, except return things. That indeed won’t work (not sure if it will give a compiler error or just result in nothing getting printed, never tried something like that).
How do you write a void method in Java?
The void Keyword
This method is a void method, which does not return any value. Call to a void method must be a statement i.e. methodRankPoints(255.7);. It is a Java statement which ends with a semicolon as shown in the following example.
What is void print in Java?
void is not an object. All the void return type states is that nothing will be returned from the method. So the answer is no, there is no way to print void, as there is nothing to print.
How do you print a method in Java?
- import java.io.PrintWriter;
- public class JavaPrintWriterPrintExample1 {
- public static void main(String[] args) {
- PrintWriter pw = new PrintWriter(System.out);
- System.out.println(“Printing boolean…”);
- boolean b=true;
- pw.print(b);
- pw.flush();
How do I return a void?
A void function can return
A void function cannot return any values. But we can use the return statement. It indicates that the function is terminated. It increases the readability of code.
Are void methods bad Java?
I will say it one more time just to be clear: in most cases void methods are bad and should be considered anti-pattern, using them may lead to a very tasteful spaghetti code where everything is implicitly stateful.
What is a void method?
Void methods are essentially methods that lives on side-effects. If a method gave no output and produced no side-effects, no one would write it, and no one would call it.
What is void class in Java?
The Void class is an uninstantiable placeholder class to hold a reference to the Class object representing the Java keyword void.
How do you display in Java?
The most basic way to display a string in a Java program is with the System. out. println() statement. This statement takes any strings and other variables inside the parentheses and displays them.
How do you call a void method from the main method in Java?
Call a Method
Inside main , call the myMethod() method: public class Main { static void myMethod() { System.out.println(“I just got executed!”); } public static void main(String[] args) { myMethod(); } } // Outputs “I just got executed!”
How do you call a void method from another class?
- public class method{
- public static void sayHello(){
- System. out. println(“Hello World”);
- }
- }
- public class app{
- public static void main(String[] args){
- method m = new method(); // Creating an instance from our class.
How do you output a method?
…
print() Method.
Overloaded Method | Prints |
---|---|
print(long l) | A long integer |
print(int i) | An integer |
print(object obj) | An object |
print(String s) |
Can you call a method in a print statement?
Yes, it does. The return value is what will print. Yes but as a “call” they aren’t asking for a call in the context of a print function, they want you to “call” the defined parent function “calculate_age()”… As noted above, print(calculate_age(1970)) absolutely does involve a function call.
Can you print an object in Java?
The print(Object) method of PrintStream Class in Java is used to print the specified Object on the stream. This Object is taken as a parameter. Parameters: This method accepts a mandatory parameter object which is the Object to be printed in the Stream. Return Value: This method do not returns any value.
What does a void method do in Java?
The void keyword specifies that a method should not have a return value.
How do I return a print statement in Java?
- import java.util.Scanner;
- public class Return_Value.
- {
- void input()
- {
- int x, y, z;
- Scanner s = new Scanner(System. in);
- System. out. print(“Enter first integer:”);
How do you call a main method in Java?
Call a Method
Inside main , call the myMethod() method: public class Main { static void myMethod() { System.out.println(“I just got executed!”); } public static void main(String[] args) { myMethod(); } } // Outputs “I just got executed!”
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Creating Method
Method Calling
The void Keyword
Passing Parameters by Value
Method Overloading
Using Command-Line Arguments
The this keyword
Variable Arguments(var-args)
The finalize( ) Method
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Java PrintWriter Class
Java PrintWriter print(boolean b) Method
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Example 1
Example 2
Java PrintWriter print(char c)
Syntax
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Example 4
Java PrintWriter print(char[] c ) Method
Syntax
Parameter
Exception
Example 5
Example 6
Java PrintWriter print(int i) Method
Syntax
Parameter
Example 7
Example 8
Java PrintWriter print(long l ) Method
Syntax
Parameter
Example 9
Example 2
Java PrintWriter print(float f) Method
Syntax
Parameter
Example 1
Example 2
Java PrintWriter print(double d) Method
Syntax
Parameter
Example 1
Example 2
Java PrintWriter print(String s) Method
Syntax
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Example 1
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Java PrintWriter print(object obj) Method
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How to print a void method from main method
There are several issues with your code:
1) The draw() method in the abstract class should be made abstract. Or, you could implement it as “partial” like in the solution I post further down, then without the abstract keyword at the Shape class:
2) new String(“color”) is not needed. Strings are immutable, so you can just write as below.
3) you miss specifying if your class members are private or public or protected. It is always a good idea to think about visibility of variables.
4) You try to print the diameter not the radius
5) You try to call a method on the class and not on the instance
Here is my suggestion (untested… there might be more issues that i did not see):
class Shape { protected int width, height; protected String color; public void draw() { System.out.print(“I am a ” + color”); } } // end Shape class class Rectangle extends Shape { Rectangle(int w, int h, String color) { this.width = w; this.height = h; this.color = color; } public void draw() { super(); System.out.print(” Rectangle ” + width + ” wide and ” + height + ” high.
“); } }// end Rectangle class class Circle extends Shape { Circle (int r, String color) { this.width = 2*r; this.height = 2*r; this.color = new String(color); } public void draw() { super(); System.out.print(” Circle with radius ” + (width/2) + “.
“); } } // end Circle class
later in the main method you need to do something like:
how to have a return for void method?
i know that..i was asking for smth like this… import java.util.Scanner
Public class..{ public static void main(…)
{ variable;
Scanner sc = new Scanner(System.in); Switch(choice)
{ case1 : System.out.print(“ans” + mulTest()); }
public static void mulTest()
{
}
i don’t think that would work. java is going to have a hernia about you trying to use “System.out.print(“ans” + mulTest());”. mulTest() is a void method, and the wayyou are using it there is as if it returns a string or someting. you can have mulTest() do something with a variable and then use that variable somewhere else, but you have to get the scope of the variable right(scope is where it would be visible in the application):
public class Test { static int i = 2; //you can use i throught the whole test class, //but only from where it was declared downwards. public static void main( String[] args ) { runMethod(); System.out.println( “i is equal to : ” + i ); } public static void runMethod() { i = i * 2; int p = 7; //p can only be used in runMethod(), which //means that as soon as you close the method //with the squigly bracket, then you lose p i = i + p; } }
void methods can do everything a normal method can, except return things.
Java – Methods
Java – Methods
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A Java method is a collection of statements that are grouped together to perform an operation. When you call the System.out.println() method, for example, the system actually executes several statements in order to display a message on the console.
Now you will learn how to create your own methods with or without return values, invoke a method with or without parameters, and apply method abstraction in the program design.
Creating Method
Considering the following example to explain the syntax of a method −
Syntax
public static int methodName(int a, int b) { // body }
Here,
public static − modifier
int − return type
methodName − name of the method
a, b − formal parameters
int a, int b − list of parameters
Method definition consists of a method header and a method body. The same is shown in the following syntax −
Syntax
modifier returnType nameOfMethod (Parameter List) { // method body }
The syntax shown above includes −
modifier − It defines the access type of the method and it is optional to use.
returnType − Method may return a value.
nameOfMethod − This is the method name. The method signature consists of the method name and the parameter list.
Parameter List − The list of parameters, it is the type, order, and number of parameters of a method. These are optional, method may contain zero parameters.
method body − The method body defines what the method does with the statements.
Example
Here is the source code of the above defined method called min(). This method takes two parameters num1 and num2 and returns the maximum between the two −
/** the snippet returns the minimum between two numbers */ public static int minFunction(int n1, int n2) { int min; if (n1 > n2) min = n2; else min = n1; return min; }
Method Calling
For using a method, it should be called. There are two ways in which a method is called i.e., method returns a value or returning nothing (no return value).
The process of method calling is simple. When a program invokes a method, the program control gets transferred to the called method. This called method then returns control to the caller in two conditions, when −
the return statement is executed.
it reaches the method ending closing brace.
The methods returning void is considered as call to a statement. Lets consider an example −
System.out.println(“This is tutorialspoint.com!”);
The method returning value can be understood by the following example −
int result = sum(6, 9);
Following is the example to demonstrate how to define a method and how to call it −
Example
public class ExampleMinNumber { public static void main(String[] args) { int a = 11; int b = 6; int c = minFunction(a, b); System.out.println(“Minimum Value = ” + c); } /** returns the minimum of two numbers */ public static int minFunction(int n1, int n2) { int min; if (n1 > n2) min = n2; else min = n1; return min; } }
This will produce the following result −
Output
Minimum value = 6
The void Keyword
The void keyword allows us to create methods which do not return a value. Here, in the following example we’re considering a void method methodRankPoints. This method is a void method, which does not return any value. Call to a void method must be a statement i.e. methodRankPoints(255.7);. It is a Java statement which ends with a semicolon as shown in the following example.
Example
public class ExampleVoid { public static void main(String[] args) { methodRankPoints(255.7); } public static void methodRankPoints(double points) { if (points >= 202.5) { System.out.println(“Rank:A1”); }else if (points >= 122.4) { System.out.println(“Rank:A2”); }else { System.out.println(“Rank:A3”); } } }
This will produce the following result −
Output
Rank:A1
Passing Parameters by Value
While working under calling process, arguments is to be passed. These should be in the same order as their respective parameters in the method specification. Parameters can be passed by value or by reference.
Passing Parameters by Value means calling a method with a parameter. Through this, the argument value is passed to the parameter.
Example
The following program shows an example of passing parameter by value. The values of the arguments remains the same even after the method invocation.
public class swappingExample { public static void main(String[] args) { int a = 30; int b = 45; System.out.println(“Before swapping, a = ” + a + ” and b = ” + b); // Invoke the swap method swapFunction(a, b); System.out.println(”
**Now, Before and After swapping values will be same here**:”); System.out.println(“After swapping, a = ” + a + ” and b is ” + b); } public static void swapFunction(int a, int b) { System.out.println(“Before swapping(Inside), a = ” + a + ” b = ” + b); // Swap n1 with n2 int c = a; a = b; b = c; System.out.println(“After swapping(Inside), a = ” + a + ” b = ” + b); } }
This will produce the following result −
Output
Before swapping, a = 30 and b = 45 Before swapping(Inside), a = 30 b = 45 After swapping(Inside), a = 45 b = 30 **Now, Before and After swapping values will be same here**: After swapping, a = 30 and b is 45
Method Overloading
When a class has two or more methods by the same name but different parameters, it is known as method overloading. It is different from overriding. In overriding, a method has the same method name, type, number of parameters, etc.
Let’s consider the example discussed earlier for finding minimum numbers of integer type. If, let’s say we want to find the minimum number of double type. Then the concept of overloading will be introduced to create two or more methods with the same name but different parameters.
The following example explains the same −
Example
public class ExampleOverloading { public static void main(String[] args) { int a = 11; int b = 6; double c = 7.3; double d = 9.4; int result1 = minFunction(a, b); // same function name with different parameters double result2 = minFunction(c, d); System.out.println(“Minimum Value = ” + result1); System.out.println(“Minimum Value = ” + result2); } // for integer public static int minFunction(int n1, int n2) { int min; if (n1 > n2) min = n2; else min = n1; return min; } // for double public static double minFunction(double n1, double n2) { double min; if (n1 > n2) min = n2; else min = n1; return min; } }
This will produce the following result −
Output
Minimum Value = 6 Minimum Value = 7.3
Overloading methods makes program readable. Here, two methods are given by the same name but with different parameters. The minimum number from integer and double types is the result.
Using Command-Line Arguments
Sometimes you will want to pass some information into a program when you run it. This is accomplished by passing command-line arguments to main( ).
A command-line argument is the information that directly follows the program’s name on the command line when it is executed. To access the command-line arguments inside a Java program is quite easy. They are stored as strings in the String array passed to main( ).
Example
The following program displays all of the command-line arguments that it is called with −
public class CommandLine { public static void main(String args[]) { for(int i = 0; i
result) result = numbers[i]; System.out.println(“The max value is ” + result); } } This will produce the following result −
Output
The max value is 56.5 The max value is 3.0
The finalize( ) Method
It is possible to define a method that will be called just before an object’s final destruction by the garbage collector. This method is called finalize( ), and it can be used to ensure that an object terminates cleanly.
For example, you might use finalize( ) to make sure that an open file owned by that object is closed.
To add a finalizer to a class, you simply define the finalize( ) method. The Java runtime calls that method whenever it is about to recycle an object of that class.
Inside the finalize( ) method, you will specify those actions that must be performed before an object is destroyed.
The finalize( ) method has this general form −
protected void finalize( ) { // finalization code here }
Here, the keyword protected is a specifier that prevents access to finalize( ) by code defined outside its class.
This means that you cannot know when or even if finalize( ) will be executed. For example, if your program ends before garbage collection occurs, finalize( ) will not execute.
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