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In quadrilateral ABCD above, AD is parallel to BC and CD = 1/2 AB. What is the measure of angle B ?
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ABCD is a quadrilateral. C Work out the length of – Gauthmath
ABCD is a quadrilateral. C Work out the length of BC Give your answer correct 1 decimal place. square root of 7.52+52=9.0139 cos 38=9.012+132-BC2/213 9.01 189.6 …
Source: www.gauthmath.com
Date Published: 12/5/2022
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ABCD is a quadrilateral Work out the length of BC Give your …
Click here 👆 to get an answer to your question ✍️ ABCD is a quadrilateral Work out the length of BC Give your answer to 1 decimal place.
Source: brainly.com
Date Published: 5/23/2022
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[Solved] What is the area of quadrilateral ABCD? – Testbook.com
ABCD is a quadrilateral with AB = 9 cm, BC = 40 cm, CD = 28 cm, DA = 15 cm and angle … such that PQ touches the circle at R. Find the measure of ∠POQ.
Source: testbook.com
Date Published: 9/7/2022
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ABCD is a quadrilateral. C Work out the length of
ABCD is a quadrilateral. C Calculate the length of – Gauthmath is a quadrilateral. C Calculate the length of BC Enter your answer correctly to 1 decimal place. \sqrt {7.5^{2}+5^{2}}=9.0139 \cos 38=(9.01)^{2}+(13)^{2}-(BC)^{2} /2(13) (9.01) 189.6=250.18^{\circ}BC^{2}BC=8.10 cm|
ABCD is a quadrilateral.Work out the length of BC.Give your answer correct to 1 decimal place.
The nomenclature is subject to certain universal rules. Which of the following statements violates the rules of nomenclature? （ ）
A. The names are written in Latin and printed in italics
B. If handwritten, underline the name
C. Biological names can be written in any language
If ABCD is a quadrilateral in which AB || CD and AD=BC, prove that $\angle$A=$\angle$ B.
$\begingroup$
F. Let ABCD be a quadrilateral in which AB || CD and AD=BC. Prove that $\angle$A=$\angle$ B.
My attempt:
Connect BD and AC and try to prove $ \Delta ADC \cong \Delta BCD $ .
In $ \Delta ADC \text{ and }\Delta BCD $:
$AD=BC$(given),
$DC=DC$.
I need to prove $ \angle ADC = \angle BCD$ to prove that the two triangles are congruent by the SAS congruence criterion. But I don’t know how $ \angle ADC = \angle BCD$ in above problem?
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