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In getting ready to slam-dunk the ball, a betball player
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player …
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Date Published: 11/29/2022
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In getting ready to slam-dunk the ball, a basketball player
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player …
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Solved In getting ready to slam-dunk the ball, a basketball
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5s. Assuming that the player accelerates …
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In getting ready to slam-dunk the… – Algebrator
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 8.62 m/s in 1.14 s. Assuming that the player …
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In getting ready to slam-dunk the ball, a basketball … – Brainly.in
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the …
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In getting ready to slam-dunk the ball, a basketball player …
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s. Assuming that the player accelerates …
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In getting ready to slam-dunk the ball, a basketball player …
In getting ready to slam dunk the ball, a basketball starts from rest and sprints to a speed of 6.0 m/s in 1.5s.
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Date Published: 3/13/2022
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In getting ready to slam-dunk the ball … – Jiskha Homework Help
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 11.0 m/s in 2.58 s. Assuming that the …
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Date Published: 3/15/2022
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In getting ready to slam-dunk the ball, a basketball … – Quora
The first thing you have to do is beat your defender to your “spot” with a series of post moves. Footwork is key here. Once you do, if you d a good job …
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Date Published: 11/25/2022
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SOLVED:In getting ready to slam-dunk the ball, a basketball …
In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 6.0 m/s in 1.5 s . Assuming that the player accelerates …
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Date Published: 6/16/2022
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In getting ready to slam-dunk the ball, a betball player
Numerical (second) derivative of time series data
First and second order derivatives are commonly used in chromatography to detect hidden peaks. The time series data consists of Instrumental Response vs. Time at very short time intervals (250 Hz). I wanted to calculate the second derivative of the data numerically in Excel. The simple option is that we calculate the first derivative and then calculate the first derivative of the first derivative to get the second derivative. The other way is to use the direct approach using the central difference formula for the second derivative. The question relates to the denominator of the second derivative from the central difference formula. It should be the square of the time interval. This is my understanding and it is dimensionally consistent, for example distance x (m) becomes acceleration (m/s2) as the second derivative of x.
One reviewer wrote a rather disparaging comment, saying that when the authors claim that the definition of a second derivative requires dividing by the square of the time interval, there is a lack of understanding of the “definition” of the second derivative. This reference to the square of a time interval indicates a worrying lack of understanding of the nature of the derivative d 2 d t 2 as an operator rather than an algebraic variable. Do mathematicians agree with the above comment? Can we interpret d 2 d t 2 as repeating the d operator twice divided by the square of the time interval? Many Thanks.
In getting ready to slam-dunk the…
In preparing to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 8.62 m/s in 1.14 s. Assuming the player accelerates steadily, determine the distance he runs.
First let’s write what we are given:
v_o=0
v = 8.62 m/s
t = 1.14s
x_o=0
x=?
Next we choose which kinematic equations we will use. We vote:
x=x_o+(v_o)t+(1/2)(a)(t^2)
v=v_o+at
Next, let’s use what we know:
x=(1/2)(a)(1.14^2)
8.62=a(1.14)
If we use algebrator to solve for ‘x’ we get:
x = 4.9134 m
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