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How to Solve a System of Equations Using Cramer’s Rule: Step-by-Step Method
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solve simultaneous equation 2x + 4y = 1 3x-5y=7 – Brainly.com
Solve simultaneous equation 2x + 4y = 1 3x-5y=7. 2. See answers. luana luana. \left \{ {{2x+4y=1\ \ | *(. bitsa bitsa. Answer. y=-1/2 and …
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Date Published: 5/12/2022
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Simultaneous equations 2x+4y=1 and 3x-5y=7. What do x and …
See a solution process below: Explanation: Step 1) Solve the first equation for x : 2x+4y=1. 2x+4y−4y=1−4y. 2x+0=1−4y. 2x=1−4y.
Source: socratic.org
Date Published: 5/7/2021
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What is x and y in this simultaneous equation, 2x+4y=1 and 3x …
Given 2 linear equations: 2x+4y=1; Equation #1 3x-5y=7; Equation #2 Need to find the x and y that satisfy simultaneously both equations.
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Date Published: 3/25/2021
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Solve linearequationswithtwounknowns 2x+4y=1 – Tiger Algebra
System of Linear Equations entered : [1] 2x + 4y = 1 [2] 3x – 5y = 7. Graphic Representation of the Equations : 4y + 2x = 1 -5y + 3x = 7. Solve by …
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Date Published: 9/18/2021
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Solve the simultaneous equati… | See how to solve it at QANDA
Solve the simultaneous equations 2x+4y=1 3x-5y=7.
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Date Published: 3/20/2022
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CHAPTER 13 SOLVING SIMULTANEOUS EQUATIONS
7. Solve the simultaneous equations 2x – 7y = –8. 3x + 4y = 17 … 2x + 5y = 7. (1) … Substituting in (1) gives: 2x + 5 = 7 i.e. 2x = 7 – 5 = 2 and x =.
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Date Published: 9/29/2021
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Solve the simultaneous equations 2x + 4y = 1 3x – 5y = 7 y=1.5 …
VIDEO ANSWER:Hi today in this veo we will learn the concept of solving the simultaneous linear equations by elimination method and we are …
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Date Published: 8/6/2021
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Solve the following simultaneous equations. 1/2(3x + 4y) + 1/5 …
Click here👆to get an answer to your question ✍️ Solve the following simultaneous equations. 1/2(3x + 4y) + 1/5(2x – 3y) = 1/4; 5/(3x + 4y) – 2/(2x – 3y) …
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Date Published: 2/30/2022
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Simultaneous equations #2x+4y=1 and 3x-5y=7#. What do #x# and #y# equal?
Step 1) Solve the first equation for #x# :
#2x + 4y = 1#
#2x + 4y – color(red)(4y) = 1 – color(red)(4y)#
#2x + 0 = 1 – 4y#
#2x = 1 – 4y#
#(2x)/color(red)(2) = (1 – 4y)/color(red)(2)#
#x = 1/color(red)(2) – (4y)/color(red)(2)#
#x = 1/2 – 2y#
Step 2) Substitute #(1/2 – 2y)# for #x# in the second equation and solve for #y#:
#3x – 5y = 7# becomes:
#3 (1/2 – 2 years) – 5 years = 7#
#(3 xx 1/2) – (3 xx 2y) – 5y = 7#
#3/2 – 6 years – 5 years = 7#
#3/2 – 11y = 7#
#3/2 – color(red)(3/2) – 11y = 7 – color(red)(3/2)#
#0 – 11y = (2/2 xx 7) – color(red)(3/2)#
#-11y = 14/2 – color(red)(3/2)#
#-11y = (14 – color(red)(3))/2#
#-11y = 11/2#
#-11y xx color(red)(-1/11) = 11/2 xx color(red)(-1/11)#
#(-11)/color(red)(-11)y = color(red)(cancel(color(black)(11))))/2 xx color(red)(-1/color(black)(cancel( color(red)(11))))#
#y = -1/2#
Step 3) Replace #-1/2# with #y# in the solution of the first equation at the end of Step 1 and calculate #x# :
#x = 1/2 – 2y# becomes:
#x = 1/2 – (2xx -1/2)#
#x = 1/2 – (-2/2)#
#x = 1/2 + 2/2#
#x = (1 + 2)/2#
#x = 3/2#
The solution is:
#x = 3/2# and #y = -1/2#
or
What is x and y in this simultaneous equation, 2x+4y=1 and 3x-5y=7?
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Solve linearequationswithtwounknowns 2x+4y=1;3x-5y=7 Tiger Algebra Solver
Entered linear system of equations:
[1] 2x + 4y = 1 [2] 3x – 5y = 7Graphical representation of the equations:
4y + 2x = 1 -5y + 3x = 7
Solve by substitution:
// Solve equation [2] for the variable x
[2] 3x = 5y + 7 [2]x = 5y/3 + 7/3// Substitute this for the variable x in equation [1].
[1] 2• ( 5y/3 +7/3) + 4y = 1 [1] 22y/3 = -11/3 [1] 22y = -11// Solve equation [1] for the variable y
[1] 22y = – 11[1] y = – 1/2// By now we know this much:
x = 5y/3 +7/3 y = -1/2
// Use the y value to solve for x
x = (5/3)(-1/2) +7/3 = 3/2
Solution :
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