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Code Java bị lỗi java.util.InputMismatchException – programming – Dạy Nhau Học
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public class Bank {
private String accountNumber;
private String accountHolder;
private String phone;
private String email ;
private double balance = 50000;public Bank(String acc…
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InputMismatchException (Java Platform SE 7 )
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- Summary of article content: Articles about InputMismatchException (Java Platform SE 7 ) Thrown by a Scanner to indicate that the token retrieved does not match the pattern for the expected type, or that the token is out of range for the … …
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java – Why am I getting InputMismatchException? – Stack Overflow
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- Summary of article content: Articles about java – Why am I getting InputMismatchException? – Stack Overflow Returns the next token as a double. If the next token is not a float or is out of range, InputMismatchException is thrown. Try to catch the exception …
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5 Answers
5
Not the answer you’re looking for Browse other questions tagged java input javautilscanner inputmismatchexception or ask your own question
InputMismatchException in Java – Javatpoint
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- Summary of article content: Articles about InputMismatchException in Java – Javatpoint In simple words, we get the InputMismatchException when the input type is not correct. When the Scanner expects an integer as input, and we prove float value … …
- Most searched keywords: Whether you are looking for InputMismatchException in Java – Javatpoint In simple words, we get the InputMismatchException when the input type is not correct. When the Scanner expects an integer as input, and we prove float value … java tutorial, features, history, variables, object, class, programs, operators, swith, for-loop, if-else, oops concept, inheritance, array, string, map, math, methods, examplesInputMismatchException in Java with java tutorial, features, history, variables, object, programs, operators, oops concept, array, string, map, math, methods, examples etc.
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What is InputMisMatchException in Java how do we handle it?
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- Summary of article content: Articles about What is InputMisMatchException in Java how do we handle it? Whenever you take inputs from the user using a Scanner . If the inputs passed doesn’t match the method or an InputMisMatchException is … …
- Most searched keywords: Whether you are looking for What is InputMisMatchException in Java how do we handle it? Whenever you take inputs from the user using a Scanner . If the inputs passed doesn’t match the method or an InputMisMatchException is … What is InputMisMatchException in Java how do we handle it? – From Java 1.5 Scanner class was introduced. This class accepts a File, InputStream, Path and, Stri …C, C++, Python, Java, HTML, CSS, JavaScript, SQL, PHP, jQuery, XML, DOM, Bootstrap, Tutorials, Articles, Programming, training, learning, quiz, preferences, examples, code
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InputMismatchException in Java with Examples | Java Hungry
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InputMismatchException in Java with Examples | Java Hungry
InputMismatchException is thrown by a Scanner to indicate that the token retrieved does not match the pattern for the expected type, or that the token is out of … … - Most searched keywords: Whether you are looking for
InputMismatchException in Java with Examples | Java Hungry
InputMismatchException is thrown by a Scanner to indicate that the token retrieved does not match the pattern for the expected type, or that the token is out of … - Table of Contents:
When does InputMismatchException occur
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InputMismatchException Class (Java.Util) | Microsoft Docs
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Scannerto indicate that the token retrieved does not match the pattern for the expected type, or that the token is out of range … … - Most searched keywords: Whether you are looking for InputMismatchException Class (Java.Util) | Microsoft Docs Thrown by a
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java.util.InputMismatchException. java code examples | Tabnine
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java code examples | Tabnine nextLong(); } catch (InputMismatchException e) { String token = scanner.next(); throw new InputMismatchException(“attempts to read a ‘long’ value from … … - Most searched keywords: Whether you are looking for java.util.InputMismatchException.
java code examples | Tabnine nextLong(); } catch (InputMismatchException e) { String token = scanner.next(); throw new InputMismatchException(“attempts to read a ‘long’ value from … msg = String.format(“‘%s’ expected, ‘%s’ got”, expected, actual); throw new InputMismatchException(msg); - Table of Contents:
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Code Java bị lỗi java.util.InputMismatchException
package data; public class Bank { private String accountNumber; private String accountHolder; private String phone; private String email ; private double balance = 50000; public Bank(String accountNumber, String accountHolder, String phone, String email, double balance) { this.accountNumber = accountNumber; this.accountHolder = accountHolder; this.phone = phone; this.email = email; this.balance += balance; } public void manageBankAccount() { System.out.println(“Here is your account profile”); System.out.printf(“|Account Number: %-17s|Account Holder: %-18s|Phone: %-10s|Email: %-26s|Balance: %10.2fVNĐ|
“, accountNumber, accountHolder, phone, email, balance); } }
package btvn; import data.Bank; import java.util.Scanner; public class BTVN { public static void main(String[] args) { Scanner keyBoard = new Scanner(System.in); for (int i = 1; i < 4; i++) { String accountNumber = keyBoard.nextLine(), accountHolder = keyBoard.nextLine(), phone = keyBoard.nextLine(), email = keyBoard.next(); double balance = keyBoard.nextDouble(); switch (i) { case 1: Bank bankAccount1 = new Bank(accountNumber, accountHolder, phone, email, balance); System.out.println("Account Bank 1"); bankAccount1.manageBankAccount(); break; case 2: Bank bankAccount2 = new Bank(accountNumber, accountHolder, phone, email, balance); System.out.println("Account Bank 2"); bankAccount2.manageBankAccount(); break; case 3: Bank bankAccount3 = new Bank(accountNumber, accountHolder, phone, email, balance); System.out.println("Account Bank 3"); bankAccount3.manageBankAccount(); break; } } } }
Why am I getting InputMismatchException?
Here you can see the nature of Scanner:
double nextDouble() Returns the next token as a double. If the next token is not a float or is out of range, InputMismatchException is thrown.
Try to catch the exception
try { // … } catch (InputMismatchException e) { System.out.print(e.getMessage()); //try to find out specific reason. }
UPDATE
CASE 1
I tried your code and there is nothing wrong with it. Your are getting that error because you must have entered String value. When I entered a numeric value, it runs without any errors. But once I entered String it throw the same Exception which you have mentioned in your question.
CASE 2
You have entered something, which is out of range as I have mentioned above.
I’m really wondering what you could have tried to enter. In my system, it is running perfectly without changing a single line of code. Just copy as it is and try to compile and run it.
import java.util.*; public class Test { public static void main(String… args) { new Test().askForMarks(5); } public void askForMarks(int student) { double marks[] = new double[student]; int index = 0; Scanner reader = new Scanner(System.in); while (index < student) { System.out.print("Please enter a mark (0..30): "); marks[index] = (double) checkValueWithin(0, 30); index++; } } public double checkValueWithin(int min, int max) { double num; Scanner reader = new Scanner(System.in); num = reader.nextDouble(); while (num < min || num > max) { System.out.print(“Invalid. Re-enter number: “); num = reader.nextDouble(); } return num; } }
As you said, you have tried to enter 1.0 , 2.8 and etc. Please try with this code.
InputMismatchException in Java
next → ← prev InputMismatchException in Java InputMismatchException is one of the most common exceptions in Java. The InputMissmatchException is an unchecked exception because it is a subclass of the java.lang.RuntimeException. The hierarchy for the java.util.InputMismatchException is as follows: It provides all the methods which are provided by the java.lang.Throwable and the java.lang.Object classes because it is a subclass of both these classes. Methods of java.lang.Throwable class addSuppressed(), fillInStackTrace(), getCause(), getLocalizedMessage(), getMessage(), getStackTrace(), getSuppressed(), initCause(), printStackTrace(), printStackTrace(), printStackTrace(), setStackTrace(), and toString(). Methods of java.lang.Object class clone(), equals(), finalize(), getClass(), hashCode(), notify(), notifyAll(), and wait(). To learn more about these methods, visit following: https://www.javatpoint.com/object-class https://www.javatpoint.com/post/java-throwable The InputMismatchException class has the following two constructors: InputMismatchException() It is the default constructor which constructs InputMismatchException with null as its error message string. InputMismatchException() It is a parameterized constructor which constructs the InputMismatchException, saving a reference to the error message s for retrieval by the getMessage() method. When does InputMismatchException occur? This unchecked exception is thrown by the Scanner for indicating that the retrieved token does not match the pattern for the expected type or that the token is out of range for the expected type. The java.util package provides a Scanner class to take input of primitive data types and strings from the user. It is the simplest way to read user input in java. The InputMismatchException occur when the user does not provide the proper type of input or input is out of range. In simple words, we get the InputMismatchException when the input type is not correct. When the Scanner expects an integer as input, and we provide float value as input to the Scanner, it throws the InputMismatchException. In the same way, when the Scanner expects an integer as input, and we provide Big Integer value as input to the Scanner, it will also throw the InputMismatchException. InputMismatchExceptionExample1.java // import required classes and packages package javaTpoint.MicrosoftJava; import java.util.InputMismatchException; import java.util.Scanner; // create class InputMismatchExample1 to understand how Scanner throws InputMismatchException public class InputMismatchExample1 { // main() method start public static void main(String[] args) { // create scanner class object Scanner sc = new Scanner(System.in); // use try-catch block for taking input from the user and handling exception try { System.out.println(“Enter value of a to get its square value:”); Integer a = sc.nextInt(); // we give any float value as input System.out.println((a*a)); } catch (InputMismatchException ex) { System.out.println( ex); } } } Output: InputMismatchExceptionExample2.java // import required classes and packages package javaTpoint.MicrosoftJava; import java.util.InputMismatchException; import java.util.Scanner; // create class InputMismatchExample2 to understand how Scanner throws InputMismatchException public class InputMismatchExample2{ // main() method start public static void main(String[] args) { // create scanner class object Scanner sc = new Scanner(System.in); // use try-catch block for taking input from the user and handling exception try { System.out.println(“Enter value of a to get its square value:”); Integer a = sc.nextInt(); // we give big integer value as input System.out.println((a*a)); } catch (InputMismatchException ex) { System.out.println(ex); } } } Output: How to avoid InputMismatchException It is very simple to avoid InputmismatchException in Java. There is only one simple way to avoid this exception, i.e., providing valid input(either similar type or data should be expected data type range) to the Scanner. In the above example, if we give five as input to the Scanner, the InputMismatchException will not occur. Next Topic Java ASCII Table
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