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python – django MultiValueDictKeyError error, how do I deal with it – Stack Overflow

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django MultiValueDictKeyError error, how do I deal with it

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Error django MultiValueDictKeyError | Edureka Community

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Python Examples of django.utils.datastructures.MultiValueDictKeyError

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django MultiValueDictKeyError error, how do I deal with it

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django MultiValueDictKeyError error, how do I deal with it I’m trying to save a object to my database, but it’s throwing a MultiValueDictKeyError error. The problems lies within the form, the is_private is represented by a checkbox. If the check box is NOT selected, obviously nothing is passed. This is where the error gets chucked. How do I properly deal with this exception, and catch it? The line is is_private = request.POST[ ‘is_private’ ] || Source Asked By: dotty

Answer #1: Use the MultiValueDict’s get method. This is also present on standard dicts and is a way to fetch a value while providing a default if it does not exist. is_private = request.POST.get( ‘is_private’ , False ) Generally, my_var = dict .get(, ) Answered By: adamnfish

Answer #2: Choose what is best for you: 1 is_private = request.POST.get( ‘is_private’ , False ); If is_private key is present in request.POST the is_private variable will be equal to it, if not, then it will be equal to False. 2 if ‘is_private’ in request.POST: is_private = request.POST[ ‘is_private’ ] else : is_private = False 3 from django.utils.datastructures import MultiValueDictKeyError try : is_private = request.POST[ ‘is_private’ ] except MultiValueDictKeyError: is_private = False Answered By: Silver Light

Answer #3: You get that because you’re trying to get a key from a dictionary when it’s not there. You need to test if it is in there first. try: is_private = ‘is_private’ in request.POST or is_private = ‘is_private’ in request.POST and request.POST[ ‘is_private’ ] depending on the values you’re using. Answered By: Joe

Answer #4: Why didn’t you try to define is_private in your models as default=False ? class Foo ( models.Models ): is_private = models.BooleanField(default= False ) Answered By: Edson Dota

Answer #5: Another thing to remember is that request.POST[‘keyword’] refers to the element identified by the specified html name attribute keyword . So, if your form is:

< input type = "text" name= "keyword" placeholder= "Search query" > < input type = "number" name= "results" placeholder= "Number of results" >

then, request.POST[‘keyword’] and request.POST[‘results’] will contain the value of the input elements keyword and results , respectively. Answered By: Leo

Answer #6: For me, this error occurred in my django project because of the following: I inserted a new hyperlink in my home.html present in templates folder of my project as below: < input type = "button" value = "About" onclick = "location.href='{% url 'about' %}'" > Run code snippet Hide results Expand snippet In views.py, I had the following definitions of count and about: def count ( request ): fulltext = request.GET[ ‘fulltext’ ] wordlist = fulltext.split() worddict = {} for word in wordlist: if word in worddict: worddict[word] += 1 else : worddict[word] = 1 worddict = sorted (worddict.items(), key = operator.itemgetter( 1 ),reverse= True ) return render(request, ‘count.html’ , ‘fulltext’ :fulltext, ‘count’ : len (wordlist), ‘worddict’ ::worddict}) def about ( request ): return render(request, “about.html” ) In urls.py, I had the following url patterns: urlpatterns = [ path( ‘admin/’ , admin.site.urls), path( ” ,views.homepage,name= “home” ), path( ‘eggs’ ,views.eggs), path( ‘count/’ ,views.count,name= “count” ), path( ‘about/’ ,views.count,name= “about” ), ] As can be seen in no. 3 above,in the last url pattern, I was incorrectly calling views.count whereas I needed to call views.about.

This line fulltext = request.GET[‘fulltext’] in count function (which was mistakenly called because of wrong entry in urlpatterns) of views.py threw the multivaluedictkeyerror exception. Then I changed the last url pattern in urls.py to the correct one i.e. path(‘about/’,views.about,name=”about”) , and everything worked fine. Apparently, in general a newbie programmer in django can make the mistake I made of wrongly calling another view function for a url, which might be expecting different set of parameters or passing different set of objects in its render call, rather than the intended behavior. Hope this helps some newbie programmer to django. Answered By: TNT

Answer #7: First check if the request object have the ‘is_private’ key parameter.

Most of the case’s this MultiValueDictKeyError occurred for missing

key in the dictionary-like request object. Because dictionary is an

unordered key, value pair “associative memories” or “associative

arrays” In another word. request.GET or request.POST is a dictionary-like

object containing all request parameters. This is specific to Django. The method get() returns a value for the given key if key is in the

dictionary. If key is not available then returns default value None. You can handle this error by putting : is_private = request.POST.get( ‘is_private’ , False ); Answered By: Projesh Bhoumik

#12235 (MultiValueDictKeyError when editing Inline objects) – Django

the attached simple model (Book and Author), using a custom UUID type as described here: ​http://www.gordontillman.info/computers/41-django/94-django-uuidfield-problem

If you add a book with an author, and then try to edit the authors (add a second one, edit the name, etc), you will generate this error:

MultiValueDictKeyError at /admin/gamedata/book/7432e312-d39b-11de-913b-00188b8e3ea8/ Key ‘author_set-0-id’ not found in Traceback: File “/usr/lib64/python2.6/site-packages/django/core/handlers/base.py” in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File “/usr/lib64/python2.6/site-packages/django/contrib/admin/options.py” in wrapper 226. return self.admin_site.admin_view(view)(*args, **kwargs) File “/usr/lib64/python2.6/site-packages/django/utils/decorators.py” in __call__ 23. return self.decorator(self.func)(*args, **kwargs) File “/usr/lib64/python2.6/site-packages/django/views/decorators/cache.py” in _wrapped_view_func 70. response = view_func(request, *args, **kwargs) File “/usr/lib64/python2.6/site-packages/django/contrib/admin/sites.py” in inner 186. return view(request, *args, **kwargs) File “/usr/lib64/python2.6/site-packages/django/db/transaction.py” in _commit_on_success 240. res = func(*args, **kw) File “/usr/lib64/python2.6/site-packages/django/contrib/admin/options.py” in change_view 826. instance=new_object, prefix=prefix) File “/usr/lib64/python2.6/site-packages/django/forms/models.py” in __init__ 724. queryset=qs) File “/usr/lib64/python2.6/site-packages/django/forms/models.py” in __init__ 459. super(BaseModelFormSet, self).__init__(**defaults) File “/usr/lib64/python2.6/site-packages/django/forms/formsets.py” in __init__ 44. self._construct_forms() File “/usr/lib64/python2.6/site-packages/django/forms/formsets.py” in _construct_forms 88. self.forms.append(self._construct_form(i)) File “/usr/lib64/python2.6/site-packages/django/forms/models.py” in _construct_form 737. form = super(BaseInlineFormSet, self)._construct_form(i, **kwargs) File “/usr/lib64/python2.6/site-packages/django/forms/models.py” in _construct_form 475. pk = self.data[pk_key] File “/usr/lib64/python2.6/site-packages/django/utils/datastructures.py” in __getitem__ 203. raise MultiValueDictKeyError, “Key %r not found in %r” % (key, self)

Python Examples of django.utils.datastructures.MultiValueDictKeyError

def post(self, request, *args, **kwargs): self.object = self.get_object() # set language key request.session[translation.LANGUAGE_SESSION_KEY] = request.POST[‘language’] # if a new avatar image was set, save it as the ‘old’ one self.avatar_kwargs = {‘old_avatar_name’: self.object.avatar.name} # Changing the email address should not be possible without entering the correct password!! # Normally this is a check one want in the clean-methods of those forms, but there it is not possible to access # elements of other forms, so this is a dirty workaround. # TODO maybe it is possible to provide this error to the respective clean-functions username = self.kwargs.get(‘username’) # this should make this situation TOCTOU-safe # in case it doesn’t try to use select_for_update() with transaction.atomic(): # NOTE: this has to be part of the atomic block! current_user = get_user_model().objects.get(username=username) old_email = current_user.email forms = request.POST new_email = forms[’email’] wrong_password = False if old_email != new_email: try: provided_password = forms[‘old_password’] except (TypeError, MultiValueDictKeyError): provided_password = None if(provided_password is None or provided_password == “” or authenticate(username=username, password=provided_password) is None): wrong_password = True # NOTE: in this case we shall not call save (super) if wrong_password: messages.add_message(request, messages.ERROR, _(‘You can not change the email address without entering the correct password.’ + ‘All changes have been discarded!’)) # TODO copy elements? – this might be some pain because we have to split those elements on both forms return super(EditProfilePageView, self).get(request, *args, **kwargs) response = super(EditProfilePageView, self).post(request, *args, **kwargs) current_user = get_user_model().objects.get(username=username) if response.status_code == 200: messages.add_message(request, messages.ERROR, _(‘Something went wrong, one or more field credentials are not fulfilled’)) else: messages.add_message(request, messages.SUCCESS, _(‘Profile successfully edited.’)) return response

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