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ValueError: not enough values to unpack (expected 3, got 2) · Issue #339 · facebookresearch/maskrcnn-benchmark · GitHub
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- Most searched keywords: Whether you are looking for ValueError: not enough values to unpack (expected 3, got 2) · Issue #339 · facebookresearch/maskrcnn-benchmark · GitHub Questions and Help So I followed the jupyter notebook tutorial and putted the code sequences into one file . When I compile with python I … ❓ Questions and Help So I followed the jupyter notebook tutorial and putted the code sequences into one file . When I compile with python I get this error result: Traceback (most recent call last): File “demo.py”, line 42, in predictions…
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Python 3 – ValueError: not enough values to unpack (expected 3, got 2) – Stack Overflow
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- Summary of article content: Articles about Python 3 – ValueError: not enough values to unpack (expected 3, got 2) – Stack Overflow 2. This means function unpaMembers. · 1. Your code does not fit your traceback. · Looks like you’re trying to unpack a tuple containing two … …
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ValueError: not enough values to unpack (expected 3, got 2) – bytemeta
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Valueerror: not enough values to unpack (expected 3, got 1) – CodeProject
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Python 3 – ValueError: no hay suficientes valores para desempaquetar (se esperaban 3, se obtuvieron 2) – PeakU
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- Summary of article content: Articles about Python 3 – ValueError: no hay suficientes valores para desempaquetar (se esperaban 3, se obtuvieron 2) – PeakU I have a problem with my Python 3 program. I use Mac OS X. This code is running properly. # -*- coding: utf-8 -*- #! python3 … …
- Most searched keywords: Whether you are looking for Python 3 – ValueError: no hay suficientes valores para desempaquetar (se esperaban 3, se obtuvieron 2) – PeakU I have a problem with my Python 3 program. I use Mac OS X. This code is running properly. # -*- coding: utf-8 -*- #! python3 …
Tengo un problema con mi programa Python 3. Uso Mac OS X. Este código se ejecuta correctamente.
# -*- coding: utf-8 -*- #! python3 # sendDuesReminders.py - Sends emails based on payment status in spreadsheet. import openpyxl, smtplib, sys # Open the spreadsheet and get the latest dues status. wb = openpyxl.load_workbook('duesRecords.xlsx') sheet = wb.get_sheet_by_name('Sheet1') lastCol = sheet.max_column latestMonth = sheet.cell(row=1, column=lastCol).value # Check each member's payment status. unpaidMembers = {} for r in range(2, sheet.max_row + 1): payment = sheet.cell(row=r, column=lastCol).value if payment != 'zaplacone': name = sheet.cell(row=r, column=2).value lastname = sheet.cell(row=r, column=3).value email = sheet.cell(row=r, column=4).value unpaidMembers[name] = email # Log in to email account. smtpObj = smtplib.SMTP_SSL('smtp.gmail.com', 465) smtpObj.ehlo() smtpObj.login('[email protected]', '1234') # Send out reminder emails. for name, email in unpaidMembers.items() body = "Subject: %s - przypomnienie o platnosci raty za treningi GIT Parkour. " \ "\n\nPrzypominamy o uregulowaniu wplaty za uczestnictwo: %sw treningach GIT Parkour w ." \ "\n\nRecords show that you have not paid dues for %s. Please make " \ "this payment as soon as possible."%(latestMonth, name, latestMonth) print('Sending email to %s...' % email) sendmailStatus = smtpObj.sendmail('[email protected]', email, body) if sendmailStatus != {}: print('There was a problem sending email to %s: %s' % (email, sendmailStatus)) smtpObj.quit()enter code here
Los problemas comienzan cuando intento agregar el siguiente valor al ciclo for.
# Send out reminder emails. for name, lastname, email in unpaidMembers.items() body = "Subject: %s - przypomnienie o platnosci raty za treningi GIT Parkour. " \ "\n\nPrzypominamy o uregulowaniu wplaty za uczestnictwo: %s %sw treningach GIT Parkour w ." \ "\n\nRecords show that you have not paid dues for %s. Please make " \ "this payment as soon as possible."%(latestMonth, name, lastname, latestMonth) print('Sending email to %s...' % email) sendmailStatus = smtpObj.sendmail('[email protected]', email, body)
La terminal muestra un error:
Traceback (most recent call last): File "sendDuesEmailReminder.py", line 44, in <module> for name, email, lastname in unpaidMembers.items(): ValueError: not enough values to unpack (expected 3, got 2)
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Lỗi ValueError: not enough values to unpack (expected 4, got 3) – programming – Dạy Nhau Học
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Mình là dân ngoại đạo, mới tập lập trình Python (mình dùng bản 3.5) , đang học qua quyển Learn Python The Hard Way, tới bài tập số 13 thì mình gặp lỗi và không làm tiếp được.
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Attention Required! | Cloudflare
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Want to find contours -> ValueError: not enough values to unpack (expected 3, got 2), this appears
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ValueError: not enough values to unpack (expected 3, got 2) – Katastros
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Python 3 – ValueError: not enough values to unpack (expected 3, got 2)
I have a problem with my Python 3 program. I use Mac OS X. This code is running properly.
# -*- coding: utf-8 -*- #! python3 # sendDuesReminders.py – Sends emails based on payment status in spreadsheet. import openpyxl, smtplib, sys # Open the spreadsheet and get the latest dues status. wb = openpyxl.load_workbook(‘duesRecords.xlsx’) sheet = wb.get_sheet_by_name(‘Sheet1’) lastCol = sheet.max_column latestMonth = sheet.cell(row=1, column=lastCol).value # Check each member’s payment status. unpaidMembers = {} for r in range(2, sheet.max_row + 1): payment = sheet.cell(row=r, column=lastCol).value if payment != ‘zaplacone’: name = sheet.cell(row=r, column=2).value lastname = sheet.cell(row=r, column=3).value email = sheet.cell(row=r, column=4).value unpaidMembers[name] = email # Log in to email account. smtpObj = smtplib.SMTP_SSL(‘smtp.gmail.com’, 465) smtpObj.ehlo() smtpObj.login(‘[email protected]’, ‘1234’) # Send out reminder emails. for name, email in unpaidMembers.items() body = “Subject: %s – przypomnienie o platnosci raty za treningi GIT Parkour. ” \ ”
Przypominamy o uregulowaniu wplaty za uczestnictwo: %s w treningach GIT Parkour w .” \ ”
Records show that you have not paid dues for %s. Please make ” \ “this payment as soon as possible.”%(latestMonth, name, latestMonth) print(‘Sending email to %s…’ % email) sendmailStatus = smtpObj.sendmail(‘[email protected]’, email, body) if sendmailStatus != {}: print(‘There was a problem sending email to %s: %s’ % (email, sendmailStatus)) smtpObj.quit()enter code here
Problems starts when I am trying to add next value to the for loop.
# Send out reminder emails. for name, lastname, email in unpaidMembers.items() body = “Subject: %s – przypomnienie o platnosci raty za treningi GIT Parkour. ” \ ”
Przypominamy o uregulowaniu wplaty za uczestnictwo: %s %s w treningach GIT Parkour w .” \ ”
Records show that you have not paid dues for %s. Please make ” \ “this payment as soon as possible.”%(latestMonth, name, lastname, latestMonth) print(‘Sending email to %s…’ % email) sendmailStatus = smtpObj.sendmail(‘[email protected]’, email, body)
Terminal shows error:
Valueerror: not enough values to unpack (expected 3, got 1)
Copy Code
TIMESTEP 0 id mass y 246 0.782024 0.498339 216 0.794396 0.505147
Copy Code
TIMESTEP id mass y 0 246 0.782024 0.498339
Python Copy Code
with open ( ‘ particle.txt’ , ‘ r’ ) as fin: f_data = fin.read() columns = [ ” TIMESTEP” , ” id” , ” mass” , ” y” ] data = [] previous_line = ” ” for line in f_data.split( ”
” ): if columns[ 0 ] in previous_line and columns[ 1 ] not in line: data.append({ ” TIMESTEP” : line}) elif columns[ 1 ] in previous_line and columns[ 0 ] not in line: data[ len (data)- 1 ][ ” id” ], data[ len (data)- 1 ][ ” mass” ], data[ len (data)- 1 ] [ ” y” ] = line.split( ” ” ) elif all (col not in line for col in columns): data.append({ ” TIMESTEP” : data[ len (data)- 1 ][ ” TIMESTEP” ]}) data[ len (data)- 1 ][ ” id” ], data[ len (data)- 1 ][ ” mass” ], data[ len (data)- 1 ] [ ” y” ] = line.split( ” ” ) previous_line = line df_1 = pd.DataFrame(data)
I have this data below:…..which I want to extract with columnwise arrangement in pandas dataframe like this:I have this code which is working fine if I have only three columns but not working for more than three columns and showing error: ValueError: not enough values to unpack (expected 3, got 1)
ValueError: no hay suficientes valores para desempaquetar (se esperaban 3, se obtuvieron 2)
1. Primero debe entender el significado del error
Error not enough values to unpack (expected 3, got 2) significa:
una tupla de 2 partes , pero asignada a 3 valores
y he escrito un código de demostración para mostrártelo:
#!/usr/bin/python # -*- coding: utf-8 -*- # Function: Showing how to understand ValueError ‘not enough values to unpack (expected 3, got 2)’ # Author: Crifan Li # Update: 20191212 def notEnoughUnpack(): “””Showing how to understand python error `not enough values to unpack (expected 3, got 2)`””” # a dict, which single key’s value is two part tuple valueIsTwoPartTupleDict = { “name1”: (“lastname1”, “email1”), “name2”: (“lastname2”, “email2”), } # Test case 1: got value from key gotLastname, gotEmail = valueIsTwoPartTupleDict[“name1”] # OK print(“gotLastname=%s, gotEmail=%s” % (gotLastname, gotEmail)) # gotLastname, gotEmail, gotOtherSomeValue = valueIsTwoPartTupleDict[“name1”] # -> ValueError not enough values to unpack (expected 3, got 2) # Test case 2: got from dict.items() for eachKey, eachValues in valueIsTwoPartTupleDict.items(): print(“eachKey=%s, eachValues=%s” % (eachKey, eachValues)) # same as following: # Background knowledge: each of dict.items() return (key, values) # here above eachValues is a tuple of two parts for eachKey, (eachValuePart1, eachValuePart2) in valueIsTwoPartTupleDict.items(): print(“eachKey=%s, eachValuePart1=%s, eachValuePart2=%s” % (eachKey, eachValuePart1, eachValuePart2)) # but following: for eachKey, (eachValuePart1, eachValuePart2, eachValuePart3) in valueIsTwoPartTupleDict.items(): # will -> ValueError not enough values to unpack (expected 3, got 2) pass if __name__ == “__main__”: notEnoughUnpack()
usando el efecto de depuración de VSCode :
2. Por tu código
for name, email, lastname in unpaidMembers.items():
pero error ValueError: not enough values to unpack (expected 3, got 2)
significa que cada elemento (un valor de tupla) en miembros no unpaidMembers , solo tiene 1 parte: email , cuyo código correspondiente anterior
unpaidMembers[name] = email
entonces debería cambiar el código a:
for name, email in unpaidMembers.items():
para evitar errores.
Pero, obviamente, espera un lastname adicional, por lo que debe cambiar su código anterior a
unpaidMembers[name] = (email, lastname)
y mejor cambio a mejor sintaxis:
for name, (email, lastname) in unpaidMembers.items():
entonces todo está bien y claro.
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